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Yuri [45]
3 years ago
12

Car salesman sells cars with prices ranging from $5,000 to $45,000. The histogram shows the distribution of the numbers of cars

he expects to sell over the next
10 years.
The salesman has observed that many students are looking for cars that cost less
than $5,000. If he decides to also deal in cars that cost less than $5,000 and projects selling 200 of them over the next 10 years, how will the distribution be affected?

The mean will shift to the right.

The mean and the median will be the same.

The median will shift to the right.

The mean will shift to the left.
Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
7 0
I am gonna think it is the 3rd one down but I may get it wrong so don't correct me I'm leaving
dangina [55]3 years ago
6 0

Answer:

A.  The mean will shift to the right.

B.  The mean and the median will be the same.

C.  The median will shift to the right.

<em> D.  The mean will shift to the left.</em>


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Does dose anyone know how to solve this?
solniwko [45]

Answer:

Width of rectangle = 6 m

Length of rectangle = 11 m

Step-by-step explanation:

Let width of rectangle = w

Length of rectangle = 3w-7

Area of rectangle = 66 m²

We need to find length and width of rectangle

The formula used is: Area=Length \times Width

Putting values and finding w

Area=Length \times Width\\66=(3w-7)(w)\\66=3w^2-7w\\3w^2-7w-66=0\\

Solve using quadratic formula: w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

We have a=3, b=-7, c=-66

Putting values and finding w

w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\w=\frac{-(-7)\pm\sqrt{(7)^2-4(3)(-66)}}{2(3)}\\w=\frac{7\pm\sqrt{49+792}}{6}\\w=\frac{7\pm\sqrt{841}}{6}\\w=\frac{7\pm29}{6}\\w=\frac{7+29}{6}\:,\:w=\frac{7-29}{6}\\w=6, w=-3.6

We get values of w as w=6 and w=-3.6

As we know width cannot be negative, so considering w = 6

So, Width = 6

Length = 3w-7 = 3(6)-7 = 18-7 = 11

So, Width of rectangle = 6 m

Length of rectangle = 11 m

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Step-by-step explanation:

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