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4 years ago

Which two of these are continuous data?

Mathematics

2 answers:

Semenov [28]4 years ago

6 0

Answer:

B and D

Step-by-step explanation:

mina [271]4 years ago

3 0

Answer:

B and D

Step-by-step explanation:

Age of Student --> Age of student is continues

Time taken to run one mile is also continues

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What is the rule for this table

Minchanka [31]

Y= x/ + 600
Hope this helps!

4 0

3 years ago

S 4x - 10y = -3<br> 112x + 5y = 12<br> What is the value of x in the solution in fraction form

Afina-wow [57]

Answer:

x = 21 / 228

Step-by-step explanation:

4x - 10y = - 3 -----> equation 1

112x + 5y = 12 -----> equation 2

Multiply 2 on both sides in the equation 2,

2 ( 112x + 5y = 12 )

224x + 10y = 24 -----> equation 3

Add equations 1 & 3,

4x - 10y = - 3

224x + 10y = 24

_____________

228x + 0 = 21

228x = 21

x = 21 / 228

4 0

3 years ago

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$