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Advocard [28]
3 years ago
9

Special Parallelograms

Mathematics
1 answer:
mash [69]3 years ago
6 0
Solving for the missing variable
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Recall that two angles are complementary if the sum of their measures is​ 90°. find the measures of two complementary angles if
gizmo_the_mogwai [7]
Let one angle be x
Let another angle be 17x
17x+x = 90
18x = 90
x = 90/18 = 5
one angle = x = 5
another angle = 17x =17*5 = 85
I hope it is helpful:D
8 0
3 years ago
A zoo keeper wants to fence a rectangular habitat for goats. The length of the habitat should be at least 80 feet, and the perim
MArishka [77]
<span>a. Write and graph a system of linear inequalities 
Here's the equation of a system of linear inequalities.
x >= 80
2x + 2y  <= 300 -----> y <= -x + 150

For the graph, it is attached as image.

</span>b. Write two possible solutions:<span>These are the two possible solutions to the given equation of linear inequality.

90 feet by 20 feet
110 feet by 30 feet.</span>

8 0
3 years ago
Solve the triangle. B = 36°, a = 41, c = 20
AnnyKZ [126]
C = 82.8° 

<span>b = 27.5 </span>

<span>Here's the working in case you need to see it. </span>

<span>Using Law of Cosines to first find b: </span>

<span>b² = a² + c² - 2acCOS(B) </span>

<span>b² = (41)² + (20)² - 2(41)(20)COS(36) </span>

<span>b = about 27.5 </span>

<span>Now using Law of Sines to find A </span>

<span>sin(36) / (27.5 = sin(A) / (41) </span>

<span>sin(A) = 41sin36 / 27.5 </span>

<span>sin(A) = 0.876334376145 </span>

<span>A = SinInverse(0.876334376145) </span>

<span>A = about 61.2° </span>

<span>Now using 180-61.2-36 to find B = 82.8° </span>

<span>Have a good day! </span>
7 0
4 years ago
Noah is thinking of two fractions that have a sum of 3/5 each fraction has a numerator of 1 what are the denominators of the fra
Ratling [72]

Answer:

The denominators are 2 and 10

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
(2 fiths) to the -2nd power btw, how can i use the camra in this app
Illusion [34]

\bf ~~~~~~~~~~~~\textit{negative exponents}&#10;\\\\&#10;a^{-n} \implies \cfrac{1}{a^n}&#10;\qquad \qquad&#10;\cfrac{1}{a^n}\implies a^{-n}&#10;\qquad \qquad a^n\implies \cfrac{1}{a^{-n}}&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;\left( \cfrac{2}{5} \right)^{-2}\implies \left( \cfrac{5}{2} \right)^{+2}\implies \left( \cfrac{5^2}{2^2} \right)\implies \cfrac{25}{4}\implies 6\frac{1}{4}

5 0
3 years ago
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