Question

An engineering school reports that 59% of its students are male (M), 39% of its students are between the ages of 18 and 20 (A), and that 24% are both male and between the ages of 18 and 20.
What is the probability of a random student being chosen who is a female and is not between the ages of 18 and 20?

Your answer should be to two decimal places.

Answer 1

Answer:

.26

Step-by-step explanation:

.59 = M

.39 = A

.24= M∩A

M'∩A'= ?

M'∩A'= (M∪A)' (we call this demorgan's law)

MUA= M+A-M∩A

.59+.39-.24= .74

1-.74= .26