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velikii [3]
4 years ago
15

I would just like to know the steps to get the area

Mathematics
1 answer:
vlada-n [284]4 years ago
8 0
To start off with, I would draw a dotted line to form a rectangle and a square. Then you find the area of the square and the rectangle, and you and them together. Remember area is length times width.

Another way to solve this is draw a line from the 9 long side up and from the 6 long side out. This creates a full rectangle with out any where shapes. Find the area of the rectangle you created by drawing the lines, and subtract it from the area of the whole rectangle.

HOPE THIS HELPS!
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A large box contains 10,000 ball bearings. A random sample of 120 is chosen. The sample mean diameter is 10 mm, and the standard
ser-zykov [4K]

Answer:

Option a) A 95% confidence interval for the mean diameter of the 120 bearings in the sample is 10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}.

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 120

Sample mean = 10 mm

Standard Deviation = 0.24 mm

Formula:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}

Hence, the correct interpretation for the confidence interval is given by option a).

A 95% confidence interval for the mean diameter of the 120 bearings in the sample is 10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}.

We have to consider the factor of sampling of 120 ball bearings from a population of 10,000 ball bearings.

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3 years ago
Find the range of the data below, 12, 15, 11, 15, 13, 10, 15
morpeh [17]

Answer:5

Step-by-step explanation:

range=greatest number- smallest number

greatest number=15

smallest number=10

range=15-10

range=5

5 0
3 years ago
What is the solution to the equation below? (Round your answer to two
finlep [7]

Answer: 2.01

Step-by-step explanation:

5\ln x=3.5\\\\x=\frac{3.5}{5}\\\\x=e^{3.5/5}\\\\x \approx 2.01

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Quadrant 4

Step-by-step explanation:

Csc = 1/sin

Cos is positive in quadrants 1 and 4

Sin is negative in quadrants 3 and 4

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ABF AND BFC. PLS MARK ME BRAINLIEST. THANK YOUUUU
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