Answer:
A.) Even.
Step-by-step explanation:
If a function is an even function, then
F(-x) = f(x)
Also, if a function is an odd function, then, f(-x) = -f(x)
You are given the below function
f(x) = 1 + 3x^2 − x^4
Let x = 2
Substitute 2 for x in the function
F(x) = 1 + 3(2)^2 - (2)^4
F(x) = 1 + 3(4) - 16
F(x) = 1 + 12 - 16
F(x) = -3
Also, Substitute -2 for x in the function
F(x) = 1 + 3(-2)^2 - (-2)^4
F(x) = 1 + 3(4) - 16
F(x) = 1 + 12 - 16
F(x) = -3
Since f(-x) = f(x), we can conclude that
F(x) = 1 + 3x^2 - x^4 is even
If you think about it, a hexagon can be cut into 6 equilateral triangles. Because of this, all you need to do is find the area of one triangle and multiply it by 6. Since the side length of one triangle is 12, we know that is the base. Since the triangles that are created when cutting the equilateral triangle in half are both 30 60 90, the height must be 6(3)^1/3. We can then multiply 12 • 6 radical 3 •1/2 to get 36 radical 3. Multiply this by 6 and get 216 radical 3 units squared.
Answer:
the answer is 8
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
D has a repeating x value. Functions are only supposed to have one input for everyone output. ( no repeating x values)
Answer:
IJ = LM.
Step-by-step explanation:
The Side-angle-side postulate states that if the pair of a corresponding sides and angles formed between these sides of two triangles are equal in measurement then these two triangle are said to be congruent.
As shown in figure 1 below:
In Δ HIJ and ΔKLM,
∠I = ∠L = 20° and HI = KL = 5 units
Since the ∠I lies between HI and IJ and ∠L lies between KL and LM, ∴ if IJ = LM then Δ HIJ and ΔKLM will be congruent by SAS postulate.
