Answer:
Step-by-step explanation:
The segment addition theorem tells you ...
CD +DE = CE
x^2 +12x = 32 -2x
Subtract the right side to put this in standard form.
x^2 +14x -32 = 0
(x +16)(x -2) = 0
x = -16 or 2
In order for DE to have a positive length, we must have x > 0. So ...
CD = x^2 = 2^2 = 4
DE = 12x = 12(2) = 24
CE = 32 -2x = 32 -2(2) = 28
3 1 10
------ + --------------- = ----------
3x x +4 7x
1 1 10
------ + ------------ = ----------
x x +4 7x
x + 4 + x 10
------------------ = ----------
x(x +4) 7x
2x + 4 10
------------------ = ----------
x(x +4) 7x
7x(2x + 4) = 10x(x+4)
14x^2 + 28x = 10x^2 + 40x
4x^2 - 12x = 0
4x(x - 3) = 0
4x = 0
x = 0
x - 3 = 0
x = 3
answer x = 0 and x = 3
Domain:
{-1, 3, 6}
Range:
{4, 5, 6}
Answer:
DE≈16.1
m<E≈60.3
m<D≈29.7
Step-by-step explanation:
Answer:
The answer might be c
Step-by-step explanation:
