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3 years ago

What is the solution to the equation 2(3)x = 3x + 1?

Mathematics

2 answers:

boyakko [2]3 years ago

5 0

The answer to the question is X=1/3

Ivahew [28]3 years ago

4 0

Answer:

6x = 3x+1

3x=1

x = 1/3

Step-by-step explanation:

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Round the following numbers to the nearest len 1)7 2)23 3)1.562

Drupady [299]

1) 7 = 7.0

2) 23 = 23.0

3) 1.562 = 1.6

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2 years ago

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What is mZG? Enter your answer in the box. FGH (x-5)° (3x+24)° x°

lapo4ka [179]

Answer:

The angle for G is 121°.

Step-by-step explanation:

Given that total angles in a triangle is 180° so in order to find the angle of G, first, you hav eto find the value of x :

x + (x - 5) + (3x + 25) = 180°

5x + 20° = 180°

5x = 160°

x = 32°

Next, you have to find the angle of G :

G = 3x + 25

G = 3(32) + 25

G = 96° + 25°

G = 121°

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3 years ago

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2 years ago

What are the first 4 prime numbers

ddd [48]

2, 3, 5 and 7 the the first 4 prime numbers

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3 years ago

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A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th

umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable X is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, p = 0.09.

An item is defective irrespective of the others.

The random variable X follows a Binomial distribution with parameters n = 9 and p = 0.09.

The repair cost of the item is given by:

$C=3X^{2}+X+2$

Compute the expected cost of repair as follows:

$E(C)=E(3X^{2}+X+2)$

$=3E(X^{2})+E(X)+2$

Compute the expected value of X as follows:

$E(X)=np$

$=4\times 0.09\\=0.36$

The expected value of X is 0.36.

Compute the variance of X as follows:

$V(X)=np(1-p)$

$=4\times 0.09\times 0.91\\=0.3276\\$

The variance of X is 0.3276.

The variance can also be computed using the formula:

$V(X)=E(Y^{2})-(E(Y))^{2}$

Then the formula of $E(Y^{2})$ is:

$E(Y^{2})=V(X)+(E(Y))^{2}$

Compute the value of $E(Y^{2})$ as follows:

$E(Y^{2})=V(X)+(E(Y))^{2}$

$=0.3276+(0.36)^{2}\\=0.4572$

The expected repair cost is:

$E(C)=3E(X^{2})+E(X)+2$

$=(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73$

Thus, the expected repair cost is $3.73.

4 0

3 years ago