<span>For more difficult cases, it may be easier to draw the graph first using the domain if possible and then determine the range graphically.See if you can find the inverse function. The domain of a function's inverse function is equal to that function's range.<span>Check to see if the function repeats.</span></span>
This is a problem of maxima and minima using derivative.
In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:
V = length x width x height
That is:

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:
Surface area of the square base =

Surface area of the rectangular sides =

Therefore, the total area of the cube is:

Isolating the variable y in terms of x:

Substituting this value in V:

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

Solving for x:

Solving for y:

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ftWidth = 4 ftHeight = 2 ftAnd its volume is:
Rewritten 3x = 2/3
then x = (2/3)/3
therefore x = 0.22
So I don’t think any of them is right
Answer:
The last two
Step-by-step explanation:
Scientific notation:
a number between 1 and 10 is multiplied by a power of 10. For example, 650,000,000 can be written in scientific notation as 6.5 ✕ 10^8
Answer:
1. 42.0 meters
2. 16.8
3. 2.3
4. 24.7
5. a. 42.4 b. 10.7
6.4.01
Step-by-step explanation:
1. so by using soh cah toa: tan40 = x/50
multiply both sides by 50 : (tan40)50=x
simplify: 42.0m
2. same concept but different values: tan35=x/24
multiply 24 to both sides: (tan35)24=x
simplify : 16.8m
3. tano^-1 = 20/100
multiply both sides by tan^-1: the angle = tan^-1 (20/100)
Simplify: 2.3 degrees
4. cos o^-1 = 4.6/10
multiply both sides by cos^-1: the angle= cos^-1 (4.6/10)
simplify: 24.7
5. a. tan23= x/100
multiply 100 to both sides: x= 100(tan23)
simplify :42.4
b. you have to find the total height of the building with the antenna and then subtract the height of the building that you found in part a.
tan28=x/100
multiply 100 to both sides : (tan28)100=x
simplify 53.1
subtract the answer to part from 53.1:
53.1-42.4=10.7
6. tan15=x/5
multiply 5 to both sides: x=5(tan15)
simplify: 4.01