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Sergio [31]
3 years ago
15

How do you graph a circle x^2 + y^2=25 and the line is given y=2

Mathematics
1 answer:
Kazeer [188]3 years ago
7 0
\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}
\end{array}\\\\
-------------------------------\\\\
x^2+y^2=25\implies (x-0)^2+(y-0)^2=5^2

so notice above, the circle is centered at h,k or 0,0, the origin, and has a ratio of 5.

and y = 2, is just a horizontal line, check the picture below.

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Step-by-step explanation:

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Solve the system of equations. \begin{aligned} &-9y+4x - 20=0 \\\\ &-7y+16x-80=0 \end{aligned} ​ −9y+4x−20=0 −7y+16x−80=
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Answer:

(5 , 0)

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7 * (−9y+4x−20)=0

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Read 2 more answers
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Answer:

<h3>             None of given </h3><h3>                  x = -1²/₇ </h3>

Step-by-step explanation:

-(-10x - 8) = -(4x + 10)

  10x + 8 = -4x - 10

      -8            -8

     10x  =  -4x - 18

      +4x     +4x

     14x = -18

      ÷14    ÷14

      x = -¹⁸/₁₄ = -⁹/₇ = -1²/₇

I think you meant -(10x-8)=-(4x+10)

Then:

-(10x - 8) = -(4x + 10)

  -10x + 8 = -4x - 10

      -8            -8

     -10x  =  -4x - 18

       +4x     +4x

     -6x  =  -18

      ÷(-6)    ÷(-6)

<h3>         x = 3     D)</h3>
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4 years ago
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