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Sergio [31]
3 years ago
15

How do you graph a circle x^2 + y^2=25 and the line is given y=2

Mathematics
1 answer:
Kazeer [188]3 years ago
7 0
\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}
\end{array}\\\\
-------------------------------\\\\
x^2+y^2=25\implies (x-0)^2+(y-0)^2=5^2

so notice above, the circle is centered at h,k or 0,0, the origin, and has a ratio of 5.

and y = 2, is just a horizontal line, check the picture below.

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What is the answer to 7+y<12
LiRa [457]

Step-by-step explanation:

7 + y < 12 it can also be written as

7 + y = 12

y = 12 - 7

y = 5

or

y < 5

Hope it will help :)

3 0
3 years ago
Give the quotient in simplest form:
11Alexandr11 [23.1K]

Answer:

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3 years ago
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The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe
juin [17]

The height of container is 8 feet

<em><u>Solution:</u></em>

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

<em><u>The volume of container is given as:</u></em>

v = length \times width \times height

Given that volume of the container is 216 cubic feet

216 = l \times w \times h

Substitute eqn 1 and eqn 2 in above formula

216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0

Solve by factoring

(h-8)(h^2+4h+27) = 0

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

h - 8 = 0\\\\h = 8

Also,

h^2+4h+27 = 0

Solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}

h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}

Therefore, on solving we get,

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

<em><u>Thus solutions of "h" are:</u></em>

h = 8

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

8 0
3 years ago
A recipe requires 5 cups of sugar you can only measures using 3/4 cups how many 3/4 cups are needed for the recipe leave the ans
Firdavs [7]

Answer:

Step-by-step explanation:

5 / (3/4) =

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20/3 <==== I left it as an improper fraction

6 0
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What percentage of 128 is 96?
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So, since 100% = 128, x should equal 96, and we are trying to find x.
Multiply both sides of the equation by x.
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Cancel out the x's on the left side so
100 = 1.333(x)
75 = x
96 is 75% of 128
7 0
3 years ago
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