The area of the square is:

And the area of the circle is:
![\begin{gathered} Ac=\pi r^2 \\ Ac=\pi\cdot(3\sqrt[]{2})^2 \\ Ac=18\pi \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20Ac%3D%5Cpi%20r%5E2%20%5C%5C%20Ac%3D%5Cpi%5Ccdot%283%5Csqrt%5B%5D%7B2%7D%29%5E2%20%5C%5C%20Ac%3D18%5Cpi%20%5Cend%7Bgathered%7D)
The area of one segment is given by:
-7(4-2)+1=15-7x
-7 x 2 + 1 = 15 - 7x
-14 + 1 = 15 -7x
-13 -15= -7x
-28 = -7x
-28 / -7 = x
x=4
3x - 54 = 160 >I just flipped the equation
3x - 54 (+54) = 160 (+54) added 54 each
3x = 160
3x/3 = 160/3 >divided 3 to each side
x = 160/30
or 53.33333333333333333~
Answer:
-8x^2+26x-21
Step-by-step explanation:
(3-2x)(4x-7)
12x-8x^2-21+14x
-8x^2+12x+14x-21
-8x^2+26x-21
Answer:
I need to see where the point is on the graph. Or at least what are the coordinates of A?
Step-by-step explanation: