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3 years ago

PLEASE ANSWER ALL PARTS I WILL GIVE BRAINLIEST

1 answer:

7 0

13.542 = 35.42*0.1 +10
13.542 is 10 more than 10% of 35.42

781 = 78.1 * 10
781 is equal to 10 times 78.1

1.2 has two significant figure but 01.20 has 3 significant figure

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For the water balloon toss the parent teacher organization needs to buy eight bags of balloons each bag is 175 balloons in it an

Black_prince [1.1K]

Answer:

1400 individual balloons

Step-by-step explanation:

Total bags of balloons needed = 8 bags

Each balloon bag contains 175 balloons.

Thus,

175 balloons × 8 = 1400 balloons.

Hence, the parent teacher association need to buy 1400 individual balloons.

8 0

4 years ago

How do you figure out 10×1000

mario62 [17]

You simply just add a 0 to the end of 1000 since you are multiplying by 10.

1000
10
--------
0000
+ 1000
----------
10,000

3 0

4 years ago

Read 2 more answers

Find the sum of the first 20 terms of an arithmetic progression of which the third term is 55 and the last term is -98

ryzh [129]

The sum of first 20 arithmetic series $S_{20}=\frac{-3475}{16}$

Given:

Arithmetic series for 3rd term is 55

Arithmetic series for 7th term is -98

To find:

The sum of first 20 Arithmetic series

<u>Step by Step Explanation: </u>

Solution:

Formula for calculating arithmetic series

Arithmetic series=a+(n-1) d

Arithmetic series for 3rd term $a_{3}=a_{1}+(3-1) d$

$a_{1}+2 d=55$

Arithmetic series for 19th term is

$a_{19}=a_{1}+(19-1) d=-98$

$a_{19}+18 d=-98$

Subtracting equation 2 from 1

$\left[a_{19}+18 d=-98\right]+\left[a_{1}+2 d=55\right]$

16d=-98-55

16d=-153

$d=\frac{-153}{16}$

Also we know $a_{1}+2 d=55$

$a_{1}+2(-153 / 16)=55$

$a_{1}+(-153 / 8)=55$

$a_{1}=55+(153 / 8)$

$a_{1}=440+153 / 8$

$a_{1}=553 / 8$

First 20 terms of an AP

$a_{n=} a_{1}+(n-1) d$

$a_{20}=553 / 8+19(-153 / 16)$

$a_{20}=\{553 * 2 / 8 * 2\}-2907 / 16$

$a_{20}=[1106 / 16]-[2907 / 16]$

$a_{20}=-1801 / 16$

Sum of 20 Arithmetic series is

$S_{n}=n\left(a_{1}+a_{n}\right) / 2$

Substitute the known values in the above equation we get

$S_{20}=\left[\frac{20\left(\left(\frac{558}{8}\right)+\left(\frac{-1801}{16}\right)\right)}{2}\right]$

$S_{20}=\left[\frac{\left.20\left(\frac{1106}{16}\right)+\left(\frac{-1801}{16}\right)\right)}{2}\right]$

$S_{20}=10 \frac{(-695 / 16)}{2}$

$S_{20}=5\left[\frac{-695}{16}\right]$

$S_{20}=\frac{-3475}{16}$

Result:

Thus the sum of first 20 terms in an arithmetic series is $S_{20}=\frac{-3475}{16}$

7 0

3 years ago

The sum of the first 200 terms of the arithmetic sequence with initial term 2 and common difference 3 is

Svetradugi [14.3K]

Answer: D. 60100

Step-by-step explanation:

The formula for determining the sum of n terms of an arithmetic sequence is expressed as

Sn = n/2[2a + (n - 1)d]

Where

n represents the number of terms in the arithmetic sequence.

d represents the common difference of the terms in the arithmetic sequence.

a represents the first term of the arithmetic sequence.

From the information given,

n = 200 terms

a = 2

d = 3

Therefore, the sum of the first 200 terms, S200 would be

S200 = 200/2[2 × 2 + (200 - 1)3]

S200 = 100[4 + 597)

S200 = 100 × 601 = 60100

8 0

4 years ago

The cost of 4 cartons of fresh cream is $7.96. What is the cost of 14 cartons WHOEVER ANSWERS FIRST IS BRAINLIEST

podryga [215]

Answer:1.99*14= 27.86 Monies

Step-by-step explanation:

3 0

2 years ago