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Oxana [17]
3 years ago
9

How do you find the fisrt quartile

Mathematics
2 answers:
dem82 [27]3 years ago
7 0
<span><span>The first quartile (Q1) is defined as the middle number between the smallest number and the median of the data set. The second quartile is the median of the data. The third quartile (Q3) is the middle value between the median and the highest value of the data set.</span></span>
lord [1]3 years ago
4 0

Answer:

Find the median of the first half of the data

Step-by-step explanation:

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400x=22,000

22,000/400=x

55=x Hopefully this is right, and hopefully this helps
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For triangle ABC, m(∠A) = 30° and m(∠B)= 115°. Which of the following lists the sides of the triangle from shortest to longest?
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Which equation would you use to find how high the bird is flying?
damaskus [11]

Answer:

The first one

Step-by-step explanation:

An easy way is SOH CAH TOA

SOH is that you use sine if you there is the opposite (in this case the question mark) and hypotenuse (the diagonal line)

CAH is that you use cosine for the adjacent side (1100) and the hypotenuse.

TOA is using tangent for the opposite and adjacent side.

To fine the question mark, you would use tangent. And plug in the given (1100 for the adjacent). So tan45 = x/1100.

If you need more help or clarification, let me know!

6 0
3 years ago
Zapisz w jak najprostszej postaci:<br> a) -x-4(1-x)<br> b) 3(5x-2)-5(3-4x)<br> c) √2(3-x)-2(1-x√2)
Sonja [21]

Answer:

Step-by-step explanation:

a) -x-4(1-x)  =

− 2 x −4 ( 1 − x ) .

2 x − 4

b) 3(5x-2)-5(3-4x)  =

3 ⋅ (5 x − 2 ) − 5 ⋅ ( 5 − 4 x )

35 x  −  31

c) √2(3-x)-2(1-x√2) =

√ 2 x ⋅ ( 3 −x ) − 2 ⋅( 1 − x √ 2 ) .

2 x √ 2 + 3 √ 2 x -√ 2 x x − 2

4 0
3 years ago
Find the perimeter of each of the two non congruent triangles where a=15,b=20 and a=29
Alborosie

Answer:

b. about 63.9 units and 41.0 units

Step-by-step explanation:

In question ∠a= 29° and Side of a= 15 and b= 20

Using sine rule of congruence of triangle.

⇒ \frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}

⇒ \frac{15}{Sin 29} = \frac{20}{sin B}

Using value of sin 29°

⇒ \frac{15}{0.49} = \frac{20}{sin B}

Cross multiplying both side.

⇒ Sin B= \frac{20\times 0.49}{15} = 0.65

∴ B= 41°

Now, we have the degree for ∠B= 41°.

Next, lets find the ∠C

∵ we know the sum total of angle of triangle is 180°

∴∠A+∠B+∠C= 180°

⇒ 29+41+B= 180

subtracting both side by 70°

∴∠C= 110°

Now, again using the sine rule to find the side of c.

\frac{b}{SinB} = \frac{c}{SinC}

⇒\frac{20}{sin41} = \frac{C}{sin110}

Using the value of sine and cross multiplying both side.

⇒ C= \frac{20\times 0.94}{0.65} = 28.92

∴ Side C= 28.92.

Now, finding perimeter of angle of triangle

Perimeter of triangle= a+b+c

Perimeter of triangle= (15+20+28.92)= 63.9

∴ Perimeter of triangle= 63.9 units

7 0
3 years ago
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