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3 years ago

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A theater wants to take in at least $2000 for the matinee. Children’s tickets cost $5 each and adult tickets cost $10 each. The

theater can seat up to 350 people. Find five combinations of children and adult tickets that will make the $2000 goal.

1 answer:

nikitadnepr [17]3 years ago

5 0

Step-by-step explanation adults=50x10=500 children 300x5=1500 1500 +500=2000

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A drawer contains 6 black neckties, 2 white neckties,4 red neckties,2 maroon neckties and 2 blue neckties. One necktie is picked

kogti [31]

A) The probability of picking a white tie 300 times = $(\frac{1}{8}) ^{300}$

B) The probability of picking a blue tie 300 times = $(\frac{1}{8}) ^{300}$

C) The probability of picking a red tie 300 times = $(\frac{1}{4}) ^{300}$

D) the probability of picking a black tie 300 times = $(\frac{3}{8}) ^{300}$

E ) the probability of picking a maroon tie 300 times = $(\frac{1}{8}) ^{300}$

F) the probability of NOT picking a white tie 300 times = $(\frac{7}{8}) ^{300}$

Step-by-step explanation:

Here, the total number of black neckties = 6

The total number of white neckties = 2

The total number of red neckties = 4

The total number of maroon neckties = 2

The total number of blue neckties = 2

The number of times the experiment is repeated = 300

A ) P(Picking a white tie) = $\frac{\textrm{Total number of white ties}}{\textrm{Total Bow ties}}$

= $\frac{2}{16} = \frac{1}{8}$

So, the probability of picking a white ONCE is 1/8.

Now, as the experiment is REPEATED 300 times with replacement.

So, the probability of picking a white tie 300 times = $(\frac{1}{8}) ^{300}$

B) P(Picking a BLUE tie) = $\frac{\textrm{Total number of blue ties}}{\textrm{Total Bow ties}} = \frac{2}{16} = \frac{1}{8}$

So, the probability of picking a blue ONCE is 1/8.

Hence, the probability of picking a blue tie 300 times = $(\frac{1}{8}) ^{300}$

C) P(Picking a Red tie) = $\frac{\textrm{Total number of Red ties}}{\textrm{Total Bow ties}} = \frac{4}{16} = \frac{1}{4}$

So, the probability of picking a red ONCE is 1/4.

Hence, the probability of picking a red tie 300 times = $(\frac{1}{4}) ^{300}$

D) P(Picking a Black tie) = $\frac{\textrm{Total number of black ties}}{\textrm{Total Bow ties}} = \frac{6}{16} = \frac{3}{8}$

So, the probability of picking a red ONCE is 3/8.

Hence, the probability of picking a black tie 300 times = $(\frac{3}{8}) ^{300}$

E) P(Picking a maroon tie) = $\frac{\textrm{Total number of maroon ties}}{\textrm{Total Bow ties}} = \frac{2}{16} = \frac{1}{8}$

So, the probability of picking a maroon ONCE is 1/8.

Hence, the probability of picking a maroon tie 300 times = $(\frac{1}{8}) ^{300}$

F) P(Picking a NOT whiten tie) = 1 - P( picking a white tie)

$= 1-(\frac{1}{8} ) = \frac{8-1}{8} = (\frac{7}{8} )$

So, the probability of NOT picking a white ONCE is 7/8.

Hence, the probability of NOT picking a white tie 300 times = $(\frac{7}{8}) ^{300}$

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Answer:

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Step-by-step explanation:

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