How many ways can you make a 3-letter arrangements out of the letters in the word trapezoid?

1 answer:

5 0

You can make 81 words from 3-letter arrangements out of the letters in trapezoid.

3-LETTER ARRANGEMENTS:

Ado, adz, aid, air, ait, ape, apo, apt, are, art, ate, azo, dap, dei, die, dip, dit, doe, dor, dot, ear, eat, era, eta, ire, oar, oat, oda, ode, ope, opt, ora, ore, ort, pad, par, pat, pea, ped, per, pet, pia, pie, pit, pod, poi, pot, pro, rad, rai, rap, rat, red, rei, rep, ret, rai, rid, rip, rod, roe, rot, tad, tae, tao, tap, tar, tea, ted, tie, tip, tod, toe, top, tor, zap, zed, zep, zip, zit, zoa

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Step-by-step explanation:

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National data indicates that 35% of households own a desktop computer. In a random sample of 570 households, 40% owned a deskt

Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a desktop.

Step-by-step explanation:

We are given that National data indicates that 35% of households own a desktop computer.

In a random sample of 570 households, 40% owned a desktop computer.

Let p = population proportion of households who own a desktop computer

SO, Null Hypothesis, $H_0$ : p = 25% {means that 35% of households own a desktop computer}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 570 households who owned a desktop computer = 40%

n = sample of households = 570

So, test statistics = $\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }$

= 2.437

Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

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In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose

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Answer:3

Step-by-step explanation:

Given

There are total 40 students in a class

No of students with Pierced Nose n(N)=7

No of students with Pierced ear n(E)=36

and we know using sets