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Ahat [919]
3 years ago
10

Richard bought some grapes. He ate 5/8 pound and kept 1 1/8 pounds of grapes. He gave Chris the rest of them. How many pounds of

grapes did Richard eat and keep for himself
Mathematics
1 answer:
Furkat [3]3 years ago
4 0

Answer:

2 pounds

Step-by-step explanation:

11/8 + 5/8 = 16/8 = 2

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Please someone help i dont know this :(
steposvetlana [31]

Answer:

D) None of the above

Step-by-step explanation:

These are no supplementary or complimentary because they do not add up to 180 and to be vertical they would have to be across from each other

5 0
3 years ago
Each month, Arnold receives $1,050 for working part time at his uncle’s camera store. For each camera that he sells, he earns a
maksim [4K]

Answer:

$1,050*125x=P(x). I just need more characters.

3 0
3 years ago
measurement error that is continuous and uniformly distributed from millivolts is added to the true voltage of a circuit. then t
satela [25.4K]

Question has missing details (Full question below)

Measurement error that is continuous and uniformly distributed from –3 to +3 millivolts is added to a circuit’s true voltage. Then the measurement is rounded to the nearest millivolt so that it becomes discrete. Suppose that the true voltage is 219 millivolts. What is the mean and variance of the measured voltage

Answer:

Mean = 219

Variance = 4

Step-by-step explanation:

Given

Let X be a random variable measurement error.

X has a discrete uniform distribution as follows

a = 219 - 3 = 216

b = 219 + 3 = 222

Mean or Expected value is calculated as follows;

E(x) = ½(216+222)

E(x) = ½ * 438

E(x) = 219

Variance is calculated as follows;

Var(x) = ((b-a+1)²-1)/12

Var(x) = ((222-216+1)²-1)/12

Var(x) = (7²-1)/12

Var(x) = 48/12

Var(x) = 4

8 0
3 years ago
Find the value of x from the equation
Jobisdone [24]

\dfrac{8^{3x}}{2^{10}}=\dfrac{4^{2x}}{16} \\\dfrac{2^{3(3x)}}{2^{10}}=\dfrac{4^{2x}}{4^2} \\2^{9x-10}=4^{2x-2} \\2^{9x-10}=2^{2(2x-2)} \\2^{9x-10}=2^{4x-4} \\9x-10=4x-4 \\5x-6=0 \\5x=6 \\\boxed{x=\dfrac{6}{5}}

Hope this helps.

r3t40

3 0
3 years ago
What is the interquartile range of 45,60,40,90,60,50,75,120,90
puteri [66]
IQR = 40

1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.

We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.

40, 45, 50, 60, 60, 75, 90, 90, 120

Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;

IQR = 90 - 50 = 40



5 0
3 years ago
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