A. 2x^2 - 3x + 10 = 2x + 21
2x^2 - 3x - 2x + 10 - 21 = 0
2x^2 - 5x - 11 = 0 (quadratic equation)
2x^2 - 6x - 7 = 2x^2
2x^2 - 2x^2 - 6x - 7 = 0
-6x - 7 = 0 (not a quadratic equation)
5x^2 + 2x - 4 = 2x^2
5x^2 - 2x^2 + 2x - 4 = 0
3x^2 + 2x - 4 (quadratic equation)
5x^3 - 3x + 10 = 2x^2
5x^3 - 2x^2 - 3x + 10 = 0 (not a quadratic equation)
Therefore, options a and c can be solved using the quadratic formula.
For a segment AB, the coordinates of the middle point C are:
xc=(xa+xb)/2,
yc=(ya+yb)/2.
Now, you know points A and C. Thus we get:
xb=2×xc-xa
yb=2×yc-ya
With numerical values:
xb=2×2-(-1)=4+1=5
yb=2×3-(-5)=6+5=11
Answer: B(5, 11)
Answer:
Step-by-step explanation:
Answer:
Average speed=52 miles per hour
Step-by-step explanation:
The expression for calculating the average speed is as follows;
S=D/T
where;
S=average speed
D=distance traveled
T=time taken
In our case;
S=unknown
D=130 miles
T=2 1/2 hours=2.5 hours
replacing;
Average speed=130/2.5=52 miles per hour
Average speed=52 miles per hour