Answer:
-Exponential Decay
-Decay factor is (1-0.05)
Step-by-step explanation:
-Given that the number decreases by a defined rate each year from the initial size by 5%,
-This is an exponential decay function of the form:

Where:
is the quantity/size after time t
is the initial size
is the rate of decay
-Our function can the be written as

Hence, the decay rate/factor is 0.05
#Alternatively
The exponential decay can be of the form:

Where:
y is the size at time x, a is the initial size, x is time and b is the decay factor.
b is of the form 

Hence, the decay factor is (1-0.05)
Answer:
Here we will use algebra to find three consecutive integers whose sum is 300. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 300. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 300
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 300
3X + 3 = 300
3X + 3 - 3 = 300 - 3
3X = 297
3X/3 = 297/3
X = 99
Which means that the first number is 99, the second number is 99 + 1 and the third number is 99 + 2. Therefore, three consecutive integers that add up to 300 are 99, 100, and 101.
99 + 100 + 101 = 300
We know our answer is correct because 99 + 100 + 101 equals 300 as displayed above.
Step-by-step explanation:
Answer:
x=48 and y is 132 my guy u welcome
Answer:
Mr.Robinson; 27/40 i think.
Step-by-step explanation: To begin solving you have to make both of the denominators the same by multiplying 2/5 by 4 and 1/4 by 5 giving you 8/20 and 5/20. From there i'm pretty sure you just add the two fractions to get 13/40 leaving 27/40 to be washed.
Answer:
x = 3
y = 0
Step-by-step explanation:
The method of substitution is when one solves an equation for one of the variables, and then substitutes the expression into the other equation. After doing so, one will solve the other equation for the remaining variable and then backsolve for the first variable.
4x + 2y = 12
x = y + 3
The second equation is already sovled for parameter (x), subttiute this into the other equation,
4(y + 3) + 2y = 12
Distribute,
4y + 12 + 2y = 12
Simplify,
6y + 12 = 12
Inverse operations,
6y + 12 = 12
-12
6y = 0
/6
y = 0
Backsolve for (x), substitute the value of (y) into the equation for (x) and solve,
x = y + 3
x = 0 + 3
x = 3