Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
Answer:
The correct answer is (FALSE)
Step-by-step explanation:
(APEX)
Every angle of a square equals 90 degrees.
2x - 4 = 90 3y + 6 = 90
2x = 90 + 4 3y = 90 - 6
2x = 94 3y = 84
x = 94/2 y = 84/3
x = 47 y = 28
so x = 47 and y = 28
Answer:
x = -1
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
−46+23=46x+23
(−46+23)=46x+23(Combine Like Terms)
−23=46x+23
−23=46x+23
Step 2: Flip the equation.
46x+23=−23
Step 3: Subtract 23 from both sides.
46x+23−23=−23−23
46x=−46
Step 4: Divide both sides by 46.
46x/46 = -46/46
Answer:
the 3rd one
Step-by-step explanation:
