Answer:
Total stocked of crayfish is = 315.2
Step-by-step explanation:
Given data:
stocked of crayfish 
in 1000 gallon water tank
size of tank = 3 ft deep and 6 feet diameter
let radius of tank is r and height of tank is h m
Total stocked of crayfish is
![= 20[ 2\pi r(r+h) ft^2]](https://tex.z-dn.net/?f=%20%20%3D%2020%5B%202%5Cpi%20r%28r%2Bh%29%20ft%5E2%5D)
[1 ft = 0.3048 m]
= 315.2
Step-by-step explanation:
step 1. what is the question? solve for x? okay.
step 2. 28/54 = (2x+ 8)/(5x - 4)
step 3. 28(5x - 4) = 54(2x + 8) (cross multiplication)
step 4. 14(5x - 4) = 27(2x + 8) (divide both sides by 2)
step 5. 70x - 56 = 54x + 216 (distributive property)
step 6. 16x = 272 (group x's and add 56 to both sides)
step 7. x = 17 (divide both sides by 16).
(6g^4h^5)^2. We have to square each term individually. Remember, squaring an exponent is just multiplying the exponents together.
6^2 = 36
(g^4)^2 = g^8
(h^5)^2= h^10
The final answer: 36g^8h^10
Answer:
Roasted Steak RS=14.47
Grilled Salmon GS= 25.21
Step-by-step explanation:
It's a 2 equation system as follows
E1-> 17RS+14GS=598.95
E2-> 28RS+7GS=581.64
We assume the system has only one solution and apply the following calculation to create a single equation
E3 -> 2x E2 -E1
That way the only incognit will be RS
(28x2 - 17) RS + (7x2 - 14) GS = 581,64x2- 598,95
39RS= 564,33
We solve for RS and then use E1 to solve for GS and E2 to check the answers
It would be this one because if you find the y-intercept it is 3. And that is the only equation with 3
