Question

In the diagram below, AE = 4, EB = 3, and DE = 2. Find CE.

Answer 1

Answer: Value of CE = 6.

Explanation:

Since we have given that

AE=4

BE=3

DE=2

Let CE be x.

As we know that

When two chords intersect each other inside a circle, the products of their segments are equal.

Here, we can see that each chord is cut into two segments at the point of where they intersect.

So,

$EA.EB=EC.ED\\\\4\times 3=x\times 2\\\\12=2x\\\\\frac{12}{2}=x\\\\6=x$

Hence, value of CE = 6.