Area as a function of width, w is:
a(w)=(w-25)^2+625
for maximum area, the width will be:
a'(w)=2(w-25)+0=0
solving for w we egt
2w-50=0
2w=50
w=25 m
given that the perimeter is 100, the length will be:
100=2(L+W)
solving for L we get:
L=50-W
but W=25m
hence
L=50-25=25 m
thus the maximum area will be:
A=L*W=25*25=625m^2
That money was taken away
The first step for finding out whether or not this expression is equivalent to

is to reduce the fraction with

. You can begin to do this by dividing the terms with the same base by subtracting their exponents.

Subtract the exponents.

Now reduce the fraction with

by doing the same process. Since I just showed you how to do this,, I will skip over this.

Since we cannot simplify this expression any further,, your answer is going to be

,, which is not equivalent to

.
Let me know if you have any further questions.
:)
X^2 x 8x -3x^2 +5 x 8x -5 x 3
8x^3 -3x^2 +40x -15