All categories

3 years ago

Can you please help me graph x+y=0

1 answer:

6 0

If you subtract x from each side, it says Y = -x .
That tells you that the slope of the graph is -1, and the y-intercept is zero.

The graph is a straight line, passing through the origin.
It slopes DOWN from left to right, at an angle of 45 degrees.

You might be interested in

Sales tax is _____.

Makovka662 [10]

Answer:

Step-by-step explanation:

3 0

3 years ago

Pls help i will give brainliest

sergiy2304 [10]

Answer:

I dont know if this is correct, but I think the answer is C

Step-by-step explanation:

4 0

3 years ago

What is r+(−5r) simplified?

mestny [16]

Answer:

-4r

Step-by-step explanation:

3 0

4 years ago

Why aren’t credit cards included in m1 or m2 definition of money?

mel-nik [20]

Credit cards are not considered to be part in the m1 and m2 definition of money. Because the M1 definition of money revolves around money which are in the hands of the public and written checks, while the M2 definition of money revolves around savings accounts, time deposits of under $100,000, and balances in retail money market mutual funds. Which also includes the M1 in the M2. While, the M3 definition of money refers to the balances in institutional money funds, repurchase accountabilities dispensed by depository establishments, and the Eurodollar. It also includes M1 and M2. Credit cards are not considered to be in M1 and M2 definitions of money, since credit cards becomes part of the money transaction only, during the payment of your credit card bill.

8 0

3 years ago

According to a survey by the Administrative Management Society, one-half of U.S. companies give employees 4 weeks of vacation af

andreyandreev [35.5K]

Answer:

$P(2\leq X\leq 5)=0.875$

$P(X$

Step-by-step explanation:

Let the random X variable representing the 6 companies that give 4 weeks of vacation after 15 years of employment:

-let p=0.5 be the probability of vacation. Since the companies are independent, X assumes a binomial random variable: $P(X=x)=b(x;6,0.5)\\\\={6 \choose x}(0.5)^x(0.5)^{6-x}\\\\={6 \choose x}(0.5)^6, \ x=0,1,2,3...\ \ \ eqtn1$

#Probability that the number of companies that give vacation is anywhere from 2 to 5:

We use equation 1;

$P(2\leq X\leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\={6 \choose 2}(0.5)^6+{6 \choose 3}(0.5)^6{6 \choose 4}(0.5)^6+{6 \choose 5}(0.5)^6\\\\=0.0156(15+20+15+6)\\\\=0.875$

Hence the probability that between 2 and 5 companies give vacation is 0.875

b. The probability that fewer than 3 companies give vacation is calculated as:

From equation one we get:

$P(X$

Hence the probability that less than three companies give vacation is 0.3432

3 0

3 years ago