Eururhtntbtbthtgrhr 13733
Its 2x^2-4x, to check it add it to 3x^2-2x or
2x^(2)-4x+3x^(2)-2x
for these you need to rearrange the equations and do substitutions.
#3 = if x+y=5 then you know x = 5-y
now substitute that equation for x in the 2nd one so x + 2y = 8 becomes
5-y + 2y = 8 2y - y becomes 1y which becomes y then subtract 5 from each side to get y =3
now replace y with 3 in the first equation x = 5-3 so x = 2
so (2,3) is the answer
same type of work for #4
2x-y=6 ,S0 y = 2X+6
so now you have 4x+2(2x+6)=-4
that becomes 4x +4x+12 = -4
8x+8 = 1, x =1
y = 2(1)-6 = -4
so answer is (1,-4)
Answer:
that is the equation of the line, its slope is 1 and the y-intercept is 1 y = x + 1
Step-by-step explanation:
we can calculate the slope of this line passing through (4,5) and (8,9) like this:
m = (y2 - y1)/(x2 - x1)
m = (9 - 5)/(8 - 4)
m = 4/4
m = 1
so the slope is 1, and now we can use the equation of one point and the slope to write the line's equation:
y - y1 = m(x - x1)
y - 5 = 1*(x - 4)
y - 5 = x - 4
y = x + 1
that is the equation of the line, its slope is 1 and the y-intercept is 1