Hello :
<span> sin 2x = sin x and 0 ≤ x ≤ 2π.
all solutions :
2x= x +2k</span>π or x= π -x +2kπ ..... k in : Z
x = 2kπ or : x = π/2 + kπ
but :
<span>0 ≤ x ≤ 2π
</span><span>all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are :
</span>k = 0 : x=0 , x= π/2
k=1 : x=2 π , x=3π/2
Answer:
(x) =
Step-by-step explanation:
let y = f(x), then rearrange making x the subject
y = 
x + 4 ( subtract 4 from both sides )
y - 4 = x ( multiply both sides by 5 to clear the fraction )
5y - 20 = x
Change y back into terms of x with x = (x) , then
(x) = 5x - 20
<span>
2(5+c)=3(5-c)
solve for c
10+2c=15-3c
5c=5
c=1</span>
Answer: C
Step-by-step explanation:
Because if you look at the star then it will show you how it rotated.
Answer:
Step-by-step explanation:
X={0,12,23}
Y={3,12,15}
X \ Y = { 0 , 23}
X/Y means the element should be only in X. We have remove the element in X if it is in Y
In this 0 and 23 is only in X
12 is X and Y. So it wont come in X/Y
