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lora16 [44]
2 years ago
8

Baby McKenna wants to arrange 5 blocks in a row. How many different arrangements can she ​make?

Mathematics
1 answer:
kogti [31]2 years ago
4 0

Answer:

I think it 120 times

Step-by-step explanation:

hope this helps!!!

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Arranging like terms; solve the linear system using eliminationlly - 3x = 18- 3x = -16y + 33
DENIUS [597]

Solution

For this case we can do the following:

11y - 3x = 18

16y -3x = 33

We can multiply the first equation by -1 and we got:

-11y +3x =-18

16y -3x = 33

_______________

16y -11y = 33-18

5y = 15

y= 15/5 = 3

And then solving for x we got

x = -(18 -11*3)/ 3= -15/3 = 5

8 0
1 year ago
What factors of 32 add up to -12
irakobra [83]

Answer: -8 and -4

This is something you do through trial and error. Making a list or a table like shown below might help.

8 0
2 years ago
A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer
pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

Z_{o.o5}= -1.648

You reverse the standardization using the formula Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

Z_{0.95}= 1.648

1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

5 0
2 years ago
Read 2 more answers
What is the range of the function for the given domain? y = 2x − 5 D: {-2, 0, 2, 4}
rosijanka [135]

Answer:

Range of Function :  { - 9, - 5, - 1,  4 }

Step-by-step explanation:

We know that y = 2x - 5 provided the domain ( x - values ) { - 2, 0, 2, 4 }. Let us substitute each element in this set of domain as x in the equation "y = 2x - 5" as to solve for the y - values, otherwise known as the range of the function.

{ - 2, 0, 2, 4 }

y = 2( - 2 ) - 5 = - 9,

y = 2( 0 ) - 5 = - 5,

y = 2( 2 ) - 5 = - 1,

y = 2( 4 ) - 5 = 4

We have the set of y - values as { - 9, - 5, - 1, 4 }. This is the range of our function.

7 0
2 years ago
Read 2 more answers
Help me with the right answer
Nadya [2.5K]

Answer:

x = 3

y = 1

Step-by-step explanation:

9x - y = 26  ---------------(I)

9x + y = 28 ---------------(II)

9x - y = 26

9x = 26 + y

Substitute 9x = 26 + y in equation (II)

26 + y + y = 28               {add like terms}

26 + 2y = 28             {subtract 26 from both sides}

         2y = 28 - 26

        2y = 2    {divide both sides by 2}

           y = 2/2

y = 1

Substitute y =1 in equation (I)

9x - 1 = 26

9x = 26 + 1

9x = 27

x = 27/9

x = 3

x = 3

y = 1

6 0
3 years ago
Read 2 more answers
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