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Reika [66]
2 years ago
6

Calculate the area of a circle with a diameter of 6cm

Mathematics
2 answers:
USPshnik [31]2 years ago
7 0
Formula for area of circle:
A=πr²
Here diameter, d= 6 cm
Radius, r= d/2 = 6/2 = 3 cm
Put values
A= 3.14 x 3²
A=3.14 x 9
A=28.26 cm²

Answer: 28.26 cm²

UkoKoshka [18]2 years ago
4 0
Hey there!

We'll do it in terms of Pi, as a variable, and in terms of pi as 3.14

We know that since the diameter is from one side to the other in a circle, dividing it by 2 will give you the radius - the distance to the middle. We plug in this radius to our area formula:

a = \pi (r^2)
a = \pi (3^2)
a = 9\pi

If our area is 9 pi, we can multiply 9 by 3.14 to get an approximate value:

A = 3.14(9)
A = 28.26

Hope this helps!
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2 candy bars cost $0.98. At this rate, how much do 5 candy bars cost? The total cost for five candy bars is?
klio [65]

Answer:

$2.45

Step-by-step explanation:

First divide the cost by number of items. you shall get $0.49

Now multiply the cost of 1 candy bar into 5 and you shall get $2.45.

6 0
2 years ago
Pls help me it’s emergency plzz fast
earnstyle [38]

Answer:

67.3%

Step-by-step explanation:

Calculate profit = selling price - cost price

cost price = 50 × $28 = $1400

38 × $49 = $1862

12 × $40 = $480

selling price = $1862 + $480 = $2342

Profit = $2342 - $1400 = $942

% profit = \frac{profit}{cost} × 100%

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7 0
3 years ago
Two friends are hiking in Death Valley National Park. Their elevation ranges from 228 ft below sea level at
monitta

Answer:

x - 231 ≤ 459

Step-by-step explanation:

Given:

Elevation ranges below sea level  = 228 ft

Elevation ranges above sea level  = 690 ft

Elevation = x

Computation:

Ideal range = [690-228] / 2 = 231

Tolerance range = [690+228] / 2 = 459

So,

x - 231 ≤ 459

6 0
3 years ago
An arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up
Papessa [141]

Answer:

s(t)=-9.8t^2+49t+58.8

Step-by-step explanation:

We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.

We know that equation of an object's height t seconds after the launch is in form s(t)=-gt^2+v_0t+h_0, where

g = Force of gravity,

v_0 = Initial velocity,

h_0 = Initial height.

For our given scenario g=-9.8, v_0=49 and h_0=58.8. Upon substituting these values in object's height function, we will get:

s(t)=-9.8t^2+49t+58.8

Therefore, the function for the height of the arrow would be s(t)=-9.8t^2+49t+58.8.

6 0
3 years ago
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