Three factorizations for 6x^3

2 answers:

8 0

I'm not quite sure what you're asking fully, but this is what I've gathered if this is right;
6=3x2
Then the actual coefficient
x^3 = x times x times x
leading to the combination of the single line.
6x^3 = 2 times 3 times x times x times x

timofeeve [1]3 years ago

5 0

3 over 18 is the anser

You might be interested in

How to find slope intercept form with one point and the slope?

andre [41]

Slope intercept form is y = mx + b...ur slope will be in the m position and ur y int will be in the b position

examples : slope = 2 , (1,3)....x = 1 and y = 3

y = mx + b
slope(m) = 2
(1,3)...x = 1 and y = 3
now we sub and find b, the y int
3 = 2(1) + b
3 = 2 + b
3 - 2 = b
1 = b

so in slope intercept form, ur equation is : y = 2x + 1
================
another example : slope = 3 , (-2,-4)

y = mx + b
slope(m) = 3
(-2,-4)...x = -2 and y = -4
now sub and find b, the y int
-4 = 3(-2) + b
-4 = - 6 + b
-4 + 6 = b
2 = b
so ur equation is : y = 3x + 2

7 0

2 years ago

Help me i dont really understand

xenn [34]

Answer:

Step-by-step explanation:

12(6) + 1/4 • 2^2

Square the 2 first.

12(6) + 1/4 • 4

Then multiply from left to right.

72 + 1

Lastly, add.

The parenthesis around the 6 mean multiplication, not the Parenthesis that are grouping symbols if you are learning PEMDAS. So your question has no grouping symbol parenthesis. Next comes Exponents, that's why we squared the 2. Multiply and Divide come next IN THE ORDER THAT THEY APPEAR FROM LEFT TO RIGHT. Then the same method with adding and subtracting. That's called the order of operations.

3 0

2 years ago

Which phrase best describes the translation from the graph y=(x-5)^2+7 to the graph of y=(x+1)^2-2

Helga [31]

Start from the parent function $f(x)=x^2$

In the first case, you are computing

$f(x-5)+7$

In the second case, you are computing

$f(x+1)-2 /tex] There are two translation going on: when you transform [tex] f(x) \to f(x+k)$ , you translate the function horizontally, $k$ units left if $k>0$ and $k$ units right if $k$ .

On the other hand, when you transform $f(x) \to f(x)+k$ , you translate the function vertically, $k$ units up if $k>0$ and $k$ units down if $k$ .

So, the first function is the "original" parabola $f(x)=x^2$ , translated $5$ units right and $7$ units up. Likewise, the second function is the "original" parabola $f(x)=x^2$ , translated $1$ units left and $2$ units down.