By using parallel lines and transversal lines concept we can prove m∠1=m∠5.
Given that, a║b and both the lines are intersected by transversal t.
We need to prove that m∠1=m∠5.
<h3>What is a transversal?</h3>
In geometry, a transversal is a line that passes through two lines in the same plane at two distinct points.
m∠1+m∠3= 180° (Linear Pair Theorem)
m∠5+m∠6=180° (Linear Pair Theorem)
m∠1+m∠3=m∠5+m∠6
m∠3=m∠6
m∠1=m∠5 (Subtraction Property of Equality)
Hence, proved. By using parallel lines and transversal lines concept we can prove m∠1=m∠5.
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Answer:
she plotted (8,5)
Step-by-step explanation:
the formula of that is (x,y). you would need to go 8 to the right and 5 units up. sophie mixed up the values.
Answer:
f=14 or f=34
Step-by-step explanation:
(x+d)(x+e) =x^2 +fx+33, d, e, f>0
x^2 +xe+dx+de=x^2+fx+33
x^2+(e+d)x+de=x^2 +fx+33 that
e+d=f and d*e=33, d=33/e
e+33/e=f
33=1*33 or 33=3*11
If e=1,d=33 then f=34
If e=3*,d=11, then f=14
The giving functions are from dofferent types. transforming a function does not change it's type so it is impossible to transfer f(x)=2 to f(x)=(x-3)^2-1.
Try A) 60 degrees; 1/2. Your answer was incorrect because cos(60 degrees) is 1/2, cos(30 degrees) is square root 3 /2 not 1 or square root 2 /2
