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3 years ago

10

A square patio has an area of 135 square feet. How long is each side of the patio to the nearest tenth?

1 answer:

Kryger [21]3 years ago

8 0

11.6 because the square root of 135 is 11.61885.... and when you check it is approximately 135 because 11.6 *11.6 = 134.56, which can be rounded to 135

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Rachel's learning to play the violin Monday through Friday she practices 45 minutes on each day on Saturday and Sundays he broug

I am Lyosha [343]

Rachel spends 6 hours 45 minutes a week trying to learn to play the violin.

Step-by-step explanation:

Step 1; Rachel learns for 45 minutes a day from Monday through Friday and in the weekend she learns to play the violin for one and a half hours. So she learns for the following periods of time

Monday - 45 minutes

Tuesday - 45 minutes

Wednesday - 45 minutes

Thursday - 45 minutes

Friday - 45 minutes

Saturday - 90 minutes (60 × 1.5 hours)

Sunday - 90 minutes (60 × 1.5 hours)

Step 2; To determine how much time she practices in a week we just add the individual times she plays on each day.

Total time practices in a week = 45 + 45 + 45 + 45 + 45 + 90 + 90 = 405 minutes = 6 hours 45 minutes.

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3 years ago

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Answer:

30 feet

Step-by-step explanation:

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If we divide both sides by cos(60), then x = 30 feet.

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3 years ago

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DochEvi [55]

B. All rectangles are parallelograms. <span />

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3 years ago

18000lb greater then or less then 9T

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3 years ago

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Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas

lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

$n(S) = n(s) + n(S \cap F)$

In which n(s) are those who are succeful but not freshmen and $n(S \cap F)$ are those who are succesful and freshmen.

By the same logic, we also have that:

$n(F) = n(f) + n(S \cap F)$

The union is:

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

In which

$n(S \cup F) = 58$

$n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)$

$n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)$

So

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

$58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)$

$n(S \cap F) = 24$

So the correct answer is:

b) 24

3 0

3 years ago