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3 years ago

If the ratio of a circles sector to its total area is 5/16 what is the measure of its sectors arc?

2 answers:

3 0

If the radius r of the circle is known, the segment length would be 2*pi*r*5/16 or r*5pi/8. (Circumference of the circle times the fraction that’s in the sector.)

Vinvika [58]3 years ago

3 0

Answer:

it is c

Step-by-step explanation:

you dot need one i just did that same test and that was the answer

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Sunny_sXe [5.5K]

I’m assuming a. Or 26 since it’s the only number within the range

7 0

3 years ago

Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)

DENIUS [597]

Compute the necessary values/derivatives of $f(x)$ at $x=1$ :

$f(1)=3$

$f'(1)=2$

$f''(1)=-12$

$f'''(1)=-12$

$f^{(4)}(1)=48$

$f^{(5)}(1)=120$

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) $f(x)$ at $x=1$ by

$T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5$

$T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5$

###

Another way of doing this would be to solve for the coefficients $a,b,c,d,e,g$ in

$f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5$

by expanding the right hand side and matching up terms with the same power of $x$ .

5 0

2 years ago

Geometry Pythagorean theorem

lara31 [8.8K]

Answer:

Below!

Step-by-step explanation:

Using Pythagoras theorem, I will solve all of the problems.

<u>Question 9:</u>

10² = 6² + x²
=> 100 = 36 + x²
=> 100 - 36 = x²
=> 64 = x²
=> x = 8

<u>Question 10:</u>

26² = 24² + x²
=> 676 = 576 + x²
=> 676 - 576 = x²
=> 100 = x²
=> x = 10

<u>Question 11:</u>

15² = 12² + x²
=> 225 = 144 + x²
=> 225 - 144 = x²
=> 81 = x²
=> x = 9

<u>Question 12:</u>

x² = 8² + 12²
=> x² = 64 + 144
=> x² = 208
=> x = √208
=> x = 14.2 (Rounded)

<u>Question 13:</u>

7² = 2² + x²
=> 49 = 4 + x²
=> 49 - 4 = x²
=> 45 = x²
=> x = √45
=> x = 6.7 (Rounded)

<u>Question 14</u>

First, let's solve for the variable x using Pythagoras theorem.

=> 5² = 3² + x²
=> 25 = 9 + x²
=> 16 = x²
=> x = 4 units

Now, let's solve for the variable y using Pythagoras theorem.

(3 + 6)² = 5² + y²
=> (9)² = 25 + y²
=> 81 = 25 + y²
=> y² = 56
=> y = √56
=> y = 7.5 (Rounded) units

Answers (Nearest tenth):

x = 4 units
y = 7.5 units

<u>Question 15:</u>

First, let's find the value of the variable y using Pythagoras theorem.

8² = 6² + y²
=> 64 = 36 + y²
=> 28 = y²
=> y = √28
=> y = 5.3 (Rounded) units

Now, let's find the value of the variable x using multiplication.

x = 2y
=> x = 2(5.3)
=> x = 10.6 units

Answer (Nearest tenth)

x = 10.6 units
y = 5.3 units

5 0

2 years ago

the sum of two numbers is 61. five times the smaller number is 23 more than the larger. find the numbers

Stella [2.4K]

Smaller Number = X
5x - 23 = Larger Number

X + (5x - 23) = 61
6x - 23 = 61
6x = 84
X = 14

6 0

2 years ago

The diagonals of a rhombus have lengths of 12 centimeters and 16 centimeters. what is the length of one side of the rhombus

Yuki888 [10]

<span>Diagonals of a rhombus are perpendicular and bisect each other. This means this rhombus is composed of four right triangles with legs of length 6 cm and 8 cm, with their hypotenuses forming the perimeter of the rhombus. The Pythagorean theorem a^2+ b^2 = c^2 can be used to find the length of the hypotenuse. 6^2+8^2 = 36+64 = 100. The square root of 100 is 10, so the length of a side of the rhombus is 10 cm.</span>

5 0

3 years ago