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Akimi4 [234]
3 years ago
13

Solve by completing the square x^2+6x+13=0

Mathematics
1 answer:
notka56 [123]3 years ago
4 0

Answer:

x = -3 + 2 i or x = -3 - 2 i

Step-by-step explanation:

Solve for x:

x^2 + 6 x + 13 = 0

Hint: | Solve the quadratic equation by completing the square.

Subtract 13 from both sides:

x^2 + 6 x = -13

Hint: | Take one half of the coefficient of x and square it, then add it to both sides.

Add 9 to both sides:

x^2 + 6 x + 9 = -4

Hint: | Factor the left hand side.

Write the left hand side as a square:

(x + 3)^2 = -4

Hint: | Eliminate the exponent on the left hand side.

Take the square root of both sides:

x + 3 = 2 i or x + 3 = -2 i

Hint: | Look at the first equation: Solve for x.

Subtract 3 from both sides:

x = -3 + 2 i or x + 3 = -2 i

Hint: | Look at the second equation: Solve for x.

Subtract 3 from both sides:

Answer: x = -3 + 2 i or x = -3 - 2 i

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The function g has an inverse. The function g − 1 determines the number of folds needed to give the folded paper a thickness of
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Answer:

\mathbf{g^{-1} (t) = log _2  \ 20 \ t}

Step-by-step explanation:

Here is the full question

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times. We'll assume we can make "perfect folds," where each fold makes the folded paper exactly twice as thick as before - and we can make as many folds as we want.

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g(n )= (05)2^n

The function g has an inverse. The function g⁻¹ determines the number of folds needed to give the folded paper a thickness of t mm. Write a function formula for g⁻¹).

<u>SOLUTION:</u>

If we represent g(n) with  t;

Then

\mathbf{t = (0.05)2^n} \\ \\ \mathbf{\dfrac{t}{0.05} = 2^n} \\ \\ \mathbf{\dfrac {100 \ t }{ 5} = 2^n} \\  \\ \mathbf{20 t = 2^n}

Taking logarithm of both sides; we have :

\mathbf{log (20 t) = n log 2}    \ \ \    \mathbf{(since  \ ,  log  \ a^b = b \ log \ a) }  \\ \\ \mathbf{n =  \dfrac{log \ 20 t }{log \ 2 }} \\ \\ \mathbf{g^{-1} (t) =  \dfrac{log \ 20 t }{log \ 2 }} \\ \\ \mathbf{g^{-1} (t) = log _2  \ 20 \ t}

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Answer:

  A-  Triangle 2: {8, 15, 17}

Step-by-step explanation:

You may recognize that the triple of choice A is a Pythagorean triple, so can be the side lengths of a right triangle.

Checking the numbers can be done nicely by a graphing calculator or spreadsheet to help avoid the tedium of doing it "by hand".

The basic idea is that the triangle will be a right triangle if the sum of the squares of the shorter sides is the square of the longer side.

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