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Zarrin [17]
3 years ago
10

$7.825 per hour × $32.125 hours round answer to the thousandth of a dollar???​

Mathematics
1 answer:
xenn [34]3 years ago
4 0
Correct it is right u have to multipl
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Enter the coordinates of the point on the unit circle at the given angle 360
kotykmax [81]

Answer:

(1, 0)

Step-by-step explanation:

360º is a full circle and is the same as 0º, so this is on the x-axis.

the y coordinate is 0

Since it's a unit circle on the x-axis the x coordinate is 1

(1, 0)

3 0
2 years ago
(n 4 - 2n 3 - 3n 2 + 7n - 2) ÷ (n - 2)
GrogVix [38]
I believe it's 

- 1 - \frac{4}{n - 2}

Hope I helped! ( Smiles )
7 0
2 years ago
Read 2 more answers
Please help, will give brainliest!
12345 [234]

Answer:

Step-by-step explanation:

In parallelogram, diagonals bisect each other

DP = IP

7x - 8 = 3x

7x       = 3x + 8

7x - 3x = 8

      4x = 8

       x = 8/4

     x = 2

NP = YP

3y = 7x - 2

3y = 7*2 - 2

3y = 14 - 2

3y = 12

y = 12/3

y = 4

6 0
3 years ago
What is the difference?
Crazy boy [7]

Answer:

<h2>D. \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\ or StartFraction x squared + 3 x minus 12 Over (x + 3) (x minus 5) (x + 7) EndFraction</h2>

Step-by-step explanation:

Given the expression \frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }, the dfference is expressed as follows;

Step1: First we need to factorize the denominator of each function.

\frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }\\= \frac{x}{x^{2}-5x+3x-15 } - \frac{4}{x^{2} + 7x-5x - 35 }\\= \frac{x}{x(x-5)+3(x-5) } - \frac{4}{x( x+ 7)x-5(x +7) }\\= \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\\\

Step 2: We will find the LCM of the resulting expression

=  \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\= \frac{x(x+7)-4(x+3)}{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+7x-4x-12 }{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\

The final expression gives the difference

6 0
3 years ago
Seth bought a 12 ounce jar of peanut butter for $ 3.60. What is the unit price?
svetlana [45]

Answer:

30

Step-by-step explanation:

7 0
3 years ago
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