Answer:
![\large\boxed{Q1.\ \left\{\begin{array}{ccc}y\leq-2x-1\\y\leq x+5\end{array}\right}\\\boxed{Q2.\ 6\leq y-3\leq8}\\\boxed{Q3.\ y\leq x-4}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BQ1.%5C%20%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Dy%5Cleq-2x-1%5C%5Cy%5Cleq%20x%2B5%5Cend%7Barray%7D%5Cright%7D%5C%5C%5Cboxed%7BQ2.%5C%206%5Cleq%20y-3%5Cleq8%7D%5C%5C%5Cboxed%7BQ3.%5C%20y%5Cleq%20x-4%7D)
Step-by-step explanation:
<, > - dotted line
≤, ≥ - solid line
<, ≤ - shaded above the line
>, ≥ - shaded below the line
<em>=================================================</em>
The slope intercept form of a line: y = mx + b
m - slope
b - y-intercept (0, b)
If m > 0, then the function is increasing
If m < 0, then the function is decreasing
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<h2>Q1.</h2>
y = -2x - 1 → m = -2 < 0 and b = -1
<em>decreasing function, y-intercept -1 → (0, -1)</em>
y = x + 5 → m = 1 > 0 and b = 5
<em>increasing function, y-intercept 5 → (0, 5)</em>
y = 2x - 1 → m = 2 > 0, and b = -1
<em>increasing function, y-intercept -1 → (0, -1)</em>
y = -x + 5 → m = -1 < 0 and b = 5
<em>decreasing function, y-intercept 5 → (0, 5)</em>
From the picture we have
<em>(1) increasing function and y-intercept 5 → </em><em>y = x + 5</em>
<em>shaded below the solid line → </em><em>y ≤ x + 5</em>
<em>(2) decreasing function and y-intercept -1 → </em><em>y = -2x - 1</em>
<em>shaded below the solid line → </em><em>y ≤ -2x - 1</em>
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<h2>
Q2.</h2>
<em>subtract 3 from both sides</em>
![9-3\leq y-3\leq11-3\\\\6\leq y-3\leq8](https://tex.z-dn.net/?f=9-3%5Cleq%20y-3%5Cleq11-3%5C%5C%5C%5C6%5Cleq%20y-3%5Cleq8)
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<h2>
Q3.</h2>
<em>solid line (≤ or ≥)</em>
<em>shaded below the line (≤ or <)</em>
<em>y ≤ x - 4</em>