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lana66690 [7]
3 years ago
10

Check out this rectangular prism. Find the surface area of the rectangle prism (above)) using its net (below)

Mathematics
1 answer:
Xelga [282]3 years ago
7 0

Answer:

48

Step-by-step explanation:

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Choose which one you believe doesn't belong.
vodka [1.7K]

Answer:

65

All the other numbers if you add up their digits it is 8.

1 + 7 = 8

2 + 6 = 8

4 + 4 = 8

6 + 5 = 11

26

Is only number divisible by 13.

44 is only divisible by 11

Step-by-step explanation:

3 0
3 years ago
Which of the following is the product for (x+4)(x-2)?
larisa86 [58]

Answer:

A

Step-by-step explanation:

X times x is x squared then x times - 2 is - 2x but 4 times x is 4x. So 4x plus - 2x is 2x. Then 4 times - 2 is - 8 put that all together you'll get x^+ 2+2x-8

6 0
3 years ago
The amount of money spent on textbooks per year for students is approximately normal.
Ostrovityanka [42]

Answer:a

a

   336.04    <  \mu < 443.96

b

  The  margin of error will increase

c

The  margin of error will decreases

d

The 99% confidence interval is  0.4107 <  p  < 0.4293

Step-by-step explanation:

From the question we are  told that

   The sample size  n =  19

    The sample mean is  \= x  = \$\  390

    The  standard deviation is  \sigma =  \$ \  120

 

Given that the confidence level is  95% then the level of significance is mathematically represented as

           \alpha = 100 -  95

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    So  

         Z_{\frac{\alpha }{2} } =  1.96

The  margin of error is mathematically represented as

      E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>    E = 1.96 *  \frac{120}{\sqrt{19} }

=>   E = 53.96

The 95% confidence interval is  

     \= x  -  E  <  \mu < \= x  +  E

=>   390  -   53.96   <  \mu < 390  -   53.96

=>  336.04    <  \mu < 443.96

When the confidence level increases the Z_{\frac{\alpha }{2} } also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         n  \  \ \alpha  \ \  \frac{1}{E^2 }

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

       \r p  =  \frac{210}{500}

       \r p  = 0.42

Given that the confidence level is 0.99 the level of significance is  \alpha =  0.01

The critical value of \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} }  =  2.58

  Generally the margin of error is mathematically represented as

       E =  Z_{\frac{\alpha }{2} }*  \sqrt{ \frac{\r p (1- \r p )}{n} }

=>   E =  0.42 *  \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }

=>     E =  0.0093

The 99% confidence interval  is

     \r p  -  E <  p  < \r p  +  E

     0.42  -  0.0093 <  p  < 0.42  +  0.0093

     0.4107 <  p  < 0.4293

 

4 0
3 years ago
Kenya exchange $200 for euros (€) suppose the conversion rate is €1 = $1.321 how many euros should kenya recieve?
____ [38]
Since 1 Euro is 1.321 in American money you must convert the value to $200
Divide 200 by 1.321
you get
151.40 in Euros 
8 0
2 years ago
What is the probability of picking an "s" in the word "footloose"?
lbvjy [14]
1/9 or 0.1111111...%
8 0
3 years ago
Read 2 more answers
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