You add another zero when you move from lesser to greater. Or like you add a total different number but is makes a major difference.
Answer: hello your question is disorganized attached below is the question and solution
answer:
1) The system has a unique solution ( x = 0, y = 0 ) ( D )
2) The system has a unique solution ( x = 0, y = 3, z = 3 ) ( D )
Step-by-step explanation:
1 ) ![\left[\begin{array}{ccc}1&0\\0&1\\0&0\end{array}\right] \left[\begin{array}{ccc}0\\0\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%5C%5C0%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
this matrix is a homogenous since there are three(3) equations and 2 variables
hence the system has a unique solution ( attached below )
2) Attached below
The matrix is a Non-homogenous system since it comprises of three(3) equations and 2 variables
Answer:
the answer is b. rational
Answer:distributing is the only operation performed in distributive property.
Step-by-step explanation:
A quadratic in vertex form reads as
(<em>x</em> - <em>a</em>)² + <em>b</em>
where (<em>a</em>, <em>b</em>) is the vertex.
To get the given quadratic in this form, complete the square:
<em>x</em>² - 6<em>x</em> - 40 = <em>x</em>² - 6<em>x</em> + 9 - 49 = (<em>x</em> - 3)² - 49
Or, work backwards by expanding the vertex form and solving for <em>a</em> and <em>b</em> :
(<em>x</em> - <em>a</em>)² + <em>b</em> = <em>x</em>² - 2<em>ax</em> + <em>a</em>² + <em>b</em>
So if
<em>x</em>² - 6<em>x</em> - 40 = <em>x</em>² - 2<em>ax</em> + <em>a</em>² + <em>b</em>,
then
-2<em>a</em> = -6 → <em>a</em> = 3
<em>a</em>² + <em>b</em> = -40 → <em>b</em> = -49
