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solong [7]
3 years ago
6

Hi I really need help with a and b. thank you

Mathematics
1 answer:
Len [333]3 years ago
6 0
A) To solve this equation, you would need to fill in the blank with a substitute. Let x represent the unknown number. 
\frac{27}{45} = \frac{x}{5}

Next, you would cross multiply. 
135 = 45x

Now, the last step would be to isolate the x. To do this, you would divide both sides by 45. 
3 = x

\frac{27}{45} = \frac{3}{5}

b) To solve this equation, you would need to fill in the blank with a substitute. Let x represent the unknown number. 
\frac{2}{6} = \frac{3}{x}
Next, you would cross multiply. 
18 = 2x

Now, the last step would be to isolate the x. To do this, you would divide both sides by 2. 
9 = x

\frac{2}{6} =\frac{3}{9}

I hope this helps!
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a gallon of unleaded gasoline weights about 6 pounds.About how many ounces does 1 quart of leaded gasoline weight?
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24 ounces are how much 1 quart of leaded gasoline weighs 
3 0
3 years ago
Read 2 more answers
A company is in the business of finding addresses of long-lost friends. The company claims to have a 70% success rate. Suppose t
Galina-37 [17]

Answer:

a) Figure attached

b) E(X) =\mu= np = 9*0.7=6.3

Sd(X) =\sigma= \sqrt{np(1-p)}= \sqrt{9*0.7*(1-0.7)}=1.375

c) For the case n= 6

P(X \leq 2) = 0.9891

For the case n= 5

P(X \leq 2) = 0.9692

So then we need at least  n=5 or n=6 to satisfy the condition required.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=9, p=0.7)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

For this case we can use the following R code:

> x <- seq(0,9,by = 1)

> y <- dbinom(x,9,0.7)

> plot(x,y,main="Histogram",type = "h")

And we can see on the figure attached the solution.

We see that the higher probabilities are from 4 to 9

Part b

The expected value is given by:

E(X) =\mu= np = 9*0.7=6.3

The variance is given by:

Var (X) =\sigma^2= np(1-p) = 9*0.7*(1-0.7)= 1.89

And the standard deviation is:

Sd(X) =\sigma= \sqrt{np(1-p)}= \sqrt{9*0.7*(1-0.7)}=1.375

Part c

First we can find the probability that at least two addresses will be found in the list of 9 that we have like this:

P(X \geq 2)

We can use the complement rule and we have:

P(X \geq 2) = 1-P(X

We find the indicidual probabilities:

P(X=0)=(9C0)(0.7)^0 (1-0.7)^{9-0}=0.00001968

P(X=1)=(9C1)(0.7)^1 (1-0.7)^{9-1}=0.000413

P(X \geq 2) = 1-[0.00001968+0.000413]=0.9996

If we use the case of n=8 and we find P(X\leq 2), we got:

P(X \leq 2) = 0.9987

For the case n= 7

P(X \leq 2) = 0.9962

For the case n= 6

P(X \leq 2) = 0.9891

For the case n= 5

P(X \leq 2) = 0.9692

So then we need at least  n=5 or n=6 to satisfy the condition required.

5 0
3 years ago
What is the answer for. What is hg = 45g
goldenfox [79]
To solve hg = 45g

Apply Multiplication Property of Equality which is to multiply both sides of the equation with 1/g.
  
  hg (1/g) = 45g (1/g)
               h = 45

Or you can divide both sides with the equation with g.
      
   hg / g = 45g / g

You can cancel g to both sides.
Then, 
               h = 45

4 0
3 years ago
Please help me quick :(
Vinvika [58]

Answer:

I don't know how helpful I'll be, sorry :(

Step-by-step explanation:

So the scale factor is 1/4 reduction because the triangle P'Q'R' is smaller than the original. When reflecting the triangle P'Q'R' over the Y axis, you'll have P"Q"R". The graphing might be a little confusing but it's just a vertical reflection.

P" = (-1,0)

Q"= (0,-1)

R"= (2,-1)

Triangles PQR and P"Q"R" are not congruent because P"Q"R" has had a 1/4 reduction and a vertical reflection.

7 0
3 years ago
135 UB students were surveyed and asked how many hours a week they spent studying. The results are in the table below?
lesya692 [45]

Answer:

B) 11/27 ; c.) 5/27; D.) 17/27; E.) 3/13 ; F) 5/9

Step-by-step explanation:

- - - - - <5hrs - - (5 - 10hrs) - - (>10 hrs) - - Total

Male (M) 25 - - - - -- 25 - - - - - 20 - - - - 70

Female (F) 20 - - - - - - 30 - - - - - 15 - - - - 65

Total - - - 45 - - - - - - 55 - - - - - 35 - - - - 135

Probability = (required outcome / Total possible outcomes)

B) probability that a student studied(5 - 10 hours)

P(5 to 10 hours) = n(5 - 10 hours) / n(total) = 55/135 = 11/27

C) Find the probability that a student is a male and spends less than 5 hours studying

P(male and < 5 hours) = n(male ∩> 5 hours) / n(total) = 25/135 = 5/27

D) Find the probability that a student is a female or spends more than 10 hours studying.

P(female) + P(> 10hours) - P(Female ∩ > 10 hours) = 65/135 + 35/135 - 15/135 = 85/135 = 17/27

E.) Find the probability that a student spends more than 10 hours studying given that the student is a female?

n(Female ∩ > 10 hours) / n(Female)

15/65 = 3/13

F) Find the probability that a student is a male given that he spends less than 5 hours studying

n(male ∩ < 5hrs) / n(< 5 hours) = 25/ 45 = 5/9

5 0
4 years ago
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