PLEASE HELP ! (EASY) (x-7)^3 (x+2)^2 (x-13) <0 what are the possible values of x?
1 answer:
You might be interested in
<span>The graph is attached.
Explanation:
We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.
<span>
x-intercepts are where the data crosses the x-axis. At every one of these points, the y-coordinate will be 0; therefore we can substitute 0 for y and solve to get the value of the x-intercept.
For the first equation, we would have
8x+8(0)=64
8x=64.
Divide both sides by 8:
8x/8 = 64/8
x=8.
For the second equation,
2x-2(0)=-4
2x=-4.
Divide both sides by 2:
2x/2 = -4/2
x=-2.
y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.
For the first equation,
8(0)+8y=64
8y=64.
Divide both sides by 8:
8y/8 = 64/8
y=8.
For the second equation,
2(0)-2y=-4
-2y=-4.
Divide both sides by -2:
-2y/-2 = -4/-2
y=2.
Plot these points for both equations and connect them to draw the line.</span></span>
Explanation:
We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.
<span>
x-intercepts are where the data crosses the x-axis. At every one of these points, the y-coordinate will be 0; therefore we can substitute 0 for y and solve to get the value of the x-intercept.
For the first equation, we would have
8x+8(0)=64
8x=64.
Divide both sides by 8:
8x/8 = 64/8
x=8.
For the second equation,
2x-2(0)=-4
2x=-4.
Divide both sides by 2:
2x/2 = -4/2
x=-2.
y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.
For the first equation,
8(0)+8y=64
8y=64.
Divide both sides by 8:
8y/8 = 64/8
y=8.
For the second equation,
2(0)-2y=-4
-2y=-4.
Divide both sides by -2:
-2y/-2 = -4/-2
y=2.
Plot these points for both equations and connect them to draw the line.</span></span>
Answer:
To find an inverse function, reflect a graph of a function across the line y=x (and find the resulting equation)
To reflect a linear function in the line y=x, find points on f(x) and then swap their x and y coordinates.
Points on f(x): (0, -4) (2, 0) (5, 6)
Points reflected in line y=x: (-4, 0) (0, 2) (6, 5)
Plot points (-4, 0) (0, 2) (6, 5) and connect to form a straight line - this is the inverse of the function:
To determine the equation of f(x):
Choose 2 points on f(x): (5, 6) and (0, -4)
Calculate the slope (gradient) by using:
Using the slope-intercept form: y = mx + b
(where m is the slope and b is in the y-intercept)
From inspection of the graph, we can see the line crosses the y-axis at -4,
⇒ f(x) = 2x - 4
As the line is actually a line segment (with endpoints (0, -4) and (5, 6), then
f(x) = 2x - 4, 0 ≤ x ≤ 5
To determine the equation of :
Rewrite f(x) as
Swap the x and y:
Rearrange to make y the subject:
Replace y with
So the equation of the inverse is:
As the original function is a segment, then
(shown in blue on the attached diagram)
** I can't see any points labelled E and F on the original function. If they are the endpoints of the line segment of f(x), then they are (0, -4) and (5, 6) **
