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tensa zangetsu [6.8K]

3 years ago

13

4 hours worked for $12; 7 hours worked for $28l

1 answer:

777dan777 [17]3 years ago

5 0

Answer:

$293.00

Step-by-step explanation:

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-7.2x+3.5=-8.7x-10 help plz

m_a_m_a [10]

-7.2x + 8.7x = -3.5 - 10
1.5x = -13.5
x = -13.5/1.5
x = -9

5 0

3 years ago

I need help with this question !!!!!!!

steposvetlana [31]

Answer:

f(x) = -5 if -5 <= x <= -3

f(x) = -2 if -3 < x <= 2

f(x) = 5 if 2 < x <= 6

Step-by-step explanation:

This is a simple piece wise function. Notice there are three lines or "solutions" for y-values over a range of x-values. Also notice there are filled in and not filled in circles. If the circle is not filled in, then it is not a solution. If it is, then it is a solution.

So for this, -5 is the solution if the range of x is from -5 through -3 inclusive since it has filled in circles.

-2 is a solution if the range of x is from -3 exclusive through 2 inclusive since at -3 it's open circle and 2 is filled.

5 is a solution if the range of x is from 2 exclusive through 6 inclusive since 2 it's open circle and 6 is filled.

To right that in notation simply

f(x) = -5 if -5 <= x <= -3

f(x) = -2 if -3 < x <= 2

f(x) = 5 if 2 < x <= 6

Cheers.

6 0

3 years ago

Solve for b using the pythagorean theorem

Lostsunrise [7]

Answer:

b = 24

Step-by-step explanation:

$b^{2} = c^{2} - a^{2}$

$b^{2} = 25^{2} - 7^{2}$

$b^{2} = 625 - 49$

$\sqrt{b^{2}} = \sqrt{576}$

$b = 24$

6 0

3 years ago

The area of a rectangle is:<br> Length x Width<br> Lengh + Width + Length + Width

tatyana61 [14]

The area of a rectangle would be:
Length x width

6 0

2 years ago

Read 2 more answers

a cuboid with a volume of 924 cm3 has dimensions 4cm (x+1)cm and (x+11)cm. show clearly that x^2 +12x-220=0. show the equation b

nikdorinn [45]

Answer:

Part 1)

The equation by factorization is

$x^{2}+12x-230=(x-(-6+\sqrt{266}))(x-(-6-\sqrt{266}))$

Both values of x are

$x1=-6+\sqrt{266}$

$x2=-6-\sqrt{266}$

Part 2) The dimensions of the cuboid are

$4\ cm$ , $(-5+\sqrt{266})\ cm$ and $(5+\sqrt{266})\ cm$

Step-by-step explanation:

step 1

we know that

The volume of the cuboid is equal to

$V=LWH$

substitute the given values

$V=4(x+1)(x+11)$

$V=924\ cm^{3}$

so

$4(x+1)(x+11)=924\\4(x^{2}+11x+x+11)=924\\ 4(x^{2}+12x+11)=924\\x^{2}+12x+11=231\\x^{2}+12x-230=0$

Complete the square

$x^{2}+12x-230=0$

$x^{2}+12x=230$

$x^{2}+12x+36=230+36$

$(x+6)^{2}=266$

square root both sides

$x+6=(+/-)\sqrt{266}$

$x=-6(+/-)\sqrt{266}$

so

$x1=-6+\sqrt{266}$

$x2=-6-\sqrt{266}$

therefore

The equation by factorization is

$x^{2}+12x-230=(x-(-6+\sqrt{266}))(x-(-6-\sqrt{266}))$

step 2

Find the dimensions of the cuboid

The dimensions are

$4\ cm$

$(x+1)\ cm -----> (-6+\sqrt{266}+1)=(-5+\sqrt{266})\ cm$

$(x+11)\ cm ----> (-6+\sqrt{266}+11)=(5+\sqrt{266})\ cm$

4 0

3 years ago

Read 2 more answers