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tensa zangetsu [6.8K]
3 years ago
13

4 hours worked for $12; 7 hours worked for $28l

Mathematics
1 answer:
777dan777 [17]3 years ago
5 0

Answer:

$293.00

Step-by-step explanation:

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If G = {(-1, 7),(-8, 2),(0, 0),(6, 6)), then the range of G is
lana66690 [7]

Answer:

\{0, 2, 6, 7\}

Step-by-step explanation:

You are given the relation G = \{(-1, 7),(-8, 2),(0, 0),(6, 6)\}

This means that

f(-1)=7\\ f(-8)=0\\f(0)=0\\f(6)=6

The input values of this relation are -1,\ -8,\ 0,\ 6, so the domain of this relation is \{-8,-1,0,6\}

The output values of this relation are 7,\ 2,\ 0,\ 6, so the range of this relation is \{0, 2, 6, 7\}

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3 years ago
What is 0.03 in simplest form?
Gelneren [198K]
Well .03 is equal to 3/100 so it is already in simplest form
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Find the least common denominator (lcd) of 1/3 and 2/9 .
OLEGan [10]
The lowest common denominator of 1/3 and 2/9 = 9
8 0
3 years ago
An operations analyst counted the number of arrivals per minute at an ATM in each of 30 randomly chosen minutes. The results wer
liraira [26]

Step-by-step explanation:

since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1

So probabaility for \mathrm{X}=1 is

P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679

So expected frequency for X=1 is 0.3679^{*} 30=11.037 (or \left.11.04\right) .

8 0
3 years ago
Write the formula for the following sequence.<br>5.8, 3.6, 1.4,...<br>PLEASE SHOW YOUR WORK.​
sladkih [1.3K]

tn = t(n - 1)- 2.2

common difference is

3.6 - 5.8 = -2.2

let T1 = 5.8

T2 = 3.6

assuming we are to find T2

T2 = T(2-1) -2.2

= T1 -22

= 5.8 -2.2

= 3.6

3 0
3 years ago
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