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faust18 [17]
3 years ago
13

If 13 ounces of tea costs $3.19, how much would you expect to pay for 15 ounces of tea? (Round your answer to the nearest cent.

Mathematics
1 answer:
Musya8 [376]3 years ago
8 0

Answer: $3.68

Step-by-step explanation:

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If AABC = ADEC,<br> ZB = 3x and ZE = 6x - 39
Tom [10]

Answer:

x = 13

Step-by-step explanation:

3x = 6x - 39 solve for x

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3 years ago
Help pls my test is about to end​
azamat

Answer:

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Step-by-step explanation:

6 0
3 years ago
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Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
babunello [35]

\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=x^2+y

\dfrac{\partial f}{\partial y}=y^2+x

\dfrac{\partial f}{\partial z}=ze^z

Integrating both sides of the latter equation with respect to z tells us

f(x,y,z)=e^z(z-1)+g(x,y)

and differentiating with respect to x gives

x^2+y=\dfrac{\partial g}{\partial x}

Integrating both sides with respect to x gives

g(x,y)=\dfrac{x^3}3+xy+h(y)

Then

f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)

and differentiating both sides with respect to y gives

y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C

So the scalar potential function is

\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}

By the fundamental theorem of calculus, the work done by \vec F along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it L) in part (a) is

\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}

and \vec F does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them L_1 and L_2) of the given path. Using the fundamental theorem makes this trivial:

\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3

\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

8 0
3 years ago
Can someone help me on this mess...
serg [7]

Answer:

sas

Step-by-step explanation:

5 0
3 years ago
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What is the slope of the line passing through the points (2 5) and (-1 -4)
Elan Coil [88]

Answer:

x1 y1 x2 y2

(2 5) (-1 -4)

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( -4 -5 )/( -1 -2 )

( -1/ -1 )

m= -1/-1

Step-by-step explanation:

pls Mark me as brainleast and folow me

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3 years ago
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