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devlian [24]
2 years ago
5

Suppose a simple random sample of size n is drawn from a large population with mean and standard deviation. The sampling distrib

ution of has mean ​______ and standard deviation ​______.
Mathematics
1 answer:
lubasha [3.4K]2 years ago
3 0

The sampling distribution of x has a mean μₓ = <u> μ </u> and standard deviation σₓ =​ <u> σ/√n </u>.

In the question, we are given that a random sample of size n is drawn from a large population with mean μ and standard deviation σ.

We are asked to find the mean and the standard deviation for the sampling distribution of the variable x for this sample.

The sample mean is regularly distributed, with a mean μₓ = μ and standard deviation σₓ = σ/√n, where n is the sample size, for samples of any size taken from populations that have a normal distribution.

Thus, the sampling distribution of x has a mean μₓ= <u> μ </u> and standard deviation σₓ=​ <u> σ/√n </u>.

Learn more about sampling distribution at

brainly.com/question/14467769

#SPJ4

The provided question is incomplete. The complete question is:

"Fill in the blanks to correctly complete the sentence below.

Suppose a simple random sample of size n is drawn from a large population with mean μ and standard deviation σ.

The sampling distribution of x has mean μₓ =​______ and standard deviation σₓ =​______."

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riadik2000 [5.3K]

Answer:

P = (12/27)*(11/26) = 0.188

Step-by-step explanation:

Si todos tienen la misma probabilidad de estar en cargo de presidente y vicepresidente, entonces:

La probabilidad de que una mujer sea presidente, es igual al cociente entre el número de mujeres y el número total de personas:

p = 12/27

Ahora queremos calcular lo mismo para vicepresidente, y el cálculo es exactamente igual, con la diferencia de que en esta situación, ya hay una mujer en el cargo de presidente, entonces hay 11 mujeres que pueden ser vicepresidente, y un total de: (11 + 15 = 26 personas)

Entonces ahora la probabilidad es:

q = 11/26

La probabilidad conjunta (es decir, la probabilidad de que ambos eventos pasen) es igual al producto de las probabilidades individuales.

P = (12/27)*(11/26) = 0.188

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