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devlian [24]
2 years ago
5

Suppose a simple random sample of size n is drawn from a large population with mean and standard deviation. The sampling distrib

ution of has mean ​______ and standard deviation ​______.
Mathematics
1 answer:
lubasha [3.4K]2 years ago
3 0

The sampling distribution of x has a mean μₓ = <u> μ </u> and standard deviation σₓ =​ <u> σ/√n </u>.

In the question, we are given that a random sample of size n is drawn from a large population with mean μ and standard deviation σ.

We are asked to find the mean and the standard deviation for the sampling distribution of the variable x for this sample.

The sample mean is regularly distributed, with a mean μₓ = μ and standard deviation σₓ = σ/√n, where n is the sample size, for samples of any size taken from populations that have a normal distribution.

Thus, the sampling distribution of x has a mean μₓ= <u> μ </u> and standard deviation σₓ=​ <u> σ/√n </u>.

Learn more about sampling distribution at

brainly.com/question/14467769

#SPJ4

The provided question is incomplete. The complete question is:

"Fill in the blanks to correctly complete the sentence below.

Suppose a simple random sample of size n is drawn from a large population with mean μ and standard deviation σ.

The sampling distribution of x has mean μₓ =​______ and standard deviation σₓ =​______."

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Zepler [3.9K]

Step-by-step explanation:

with the use of Pythagoras theorem you can find each side of one triangle

I hope this helps!

5 0
3 years ago
Read 2 more answers
The manager of a restaurant found that the cost to produce 150 cups of coffee is ​$ 20.00​, while the cost to produce 400 cups i
34kurt

Answer: Our required linear equation would be 10y-x=50

Step-by-step explanation:

Since we have given that

Number of cups = 150

Cost = $20

Number of cups = 400

Cost = $45

Let x be the number of cups, y be the cost .

We will use "Equation of line using Two point slope":

y-20=\dfrac{45-20}{400-150}(x-150)\\\\y-20=\dfrac{25}{250}(x-150)\\\\10(y-20)=(x-150)\\\\10y-200=x-150\\\\10y-x=-150+200\\\\10y-x=50

Hence, our required linear equation would be 10y-x=50

4 0
3 years ago
What is the solution to the system of equations? Use any method you like, but be sure to show all work.
jeka57 [31]
These are known as simultaneous equations,,
2x + y= -3 take this as 1st equation
x-2y=-4 take this as 2 nd equation

therefore x - 2y= -2 should be multiplied by 2 inorder to cut off 2x and 2x from the first and second equations.

by multiplying we get 2x - 4y = -4

therefore 3rd equation should be substracted from 1st equation...

now, 2x -4y - 2x -y = -4-(-3)

therefore, -2x and +2x is cut.

as a result -5y= -1

therefore y = 1 /5

then let us find x

2x + y = -3
::: 2x + 1/5= -3
therefore 2x= -3-1/5

finally, x= -16/5÷2
then x= 8/5

3 0
3 years ago
What is a answer for <br> 4(8n-1)=19+32n
lord [1]

Answer:

No solution

Step-by-step explanation:

4(8n-1)=19+32n

Distribute the 4 to 8n-1

32n-4=19+32n

Add 4 on both sides

32n=23+32n

Subtract 32n on both sides.

Both 32n's cancel out so you are left with 0=23 which is false.

There is no solution

3 0
3 years ago
Screen-printing a batch of shirts requires 3 minutes per shirt in addition to 13 minutes of initial set-up time. If it takes 616
krek1111 [17]

Answer: 201 shirts

Step-by-step explanation:

Let x= total shirts in the batch.

Total time taken for x shirts = Initial set-up time + (Time require per shirt) × (x)

\Rightarrow\ 616= 13+3x\\\\\Rightarrow\ 3x=616-13\\\\\Rightarrow\ 3x= 603\\\\\Rightarrow\ x=\dfrac{603}{3}\\\\\Rightarrow\ x=201

Hence, there are 201 shirts in the batch.

3 0
3 years ago
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