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Len [333]
3 years ago
13

Perform the indicated operation. (3a2 - 7xy)(3a2 + 7xy)

Mathematics
2 answers:
Naily [24]3 years ago
8 0

(3a² - 7xy)(3a² + 7xy) =

= (3a²)² - (7xy)²

= 9a⁴ - 49x²y²

Use

a² - b² = (a - b)(a + b)

raketka [301]3 years ago
8 0

Answer:

9a^4 - 49x^2y^2.

Step-by-step explanation:

(3a^2 - 7xy)(3a^2 + 7xy)

This is example of the difference of 2 squares:

(a + b)(a - b) = a^2 - b^2,  so the answer is:

(3a^2)^2 - (7xy)^2

= 9a^4 - 49x^2y^2.

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3 years ago
What values of x make this inequality true?
Alborosie

Answer:

A. x > 13

Step-by-step explanation:

x-3>10

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3 0
3 years ago
If p, q are zeroes of polynomial f(x) =2x^2-7x+3,find the value of p^2+q^2​
Elza [17]

Answer:

p^2 + q^2 = 22/9.

Step-by-step explanation:

For a quadratic function ax^2 + bx + c if the zeroes are A and B then

A + B = -b/a and AB =  c/a.

2x^2 - 7x + 3

Now p and q are the zeroes of the above function so

p + q =  7/3 and pq = 3/2.

Now p^2 + q^2 = (p + q)^2 - 2pq

= (7/3)^2 - 2* 3/2

=  49/9 - 3

= 49/4 -  27/9

= 22/9.

4 0
3 years ago
Create a circle with a centre of (0,0) and a radius of 13
Mumz [18]

Answer:

The equation would be:

x^2+y^2=169

In the attachment!!!

<em>Hope this helps!!!</em>

<em>Sofia</em>

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