Which scale factors produce a contraction under a dilation of the original image?

Y = -2(x + 5)(x + 1)<br> Set the factor (x + 5) = 0 and solve

Harrizon [31]

Answer: $x=-5$

Step-by-step explanation:

$x+5=0 \implies x=-5$

7 0

2 years ago

This is due tomorrow, so please help and show step by step

Softa [21]

Answer:

slope = 3/2
y-intercept = 3
x-intercept = -2

Step-by-step explanation:

The slope is the coefficient of x when the equation is of the form ...

y = (something).

Here, we can put the equation in that form by subtracting 12x and dividing by the coefficient of y:

12x -8y = -24 . . . . . given

-8y = -12x -24 . . . . .subtract 12x

y = 3/2x +3 . . . . . . . divide by -8

This is the "slope-intercept" form of the equation. Generically, it is written ...

y = mx + b . . . . . . where m is the slope and b is the y-intercept

So, the above equation answers two of your questions:

slope = 3/2

y-intercept = 3

__

The x-intercept is found fairly easily from the original equation by setting y=0:

12x = -24

x = -24/12 = -2 . . . . . the x-intercept

_____

A graph of the equation can also show you these things. The graph shows a rise of 3 units for a run of 2, so the slope is rise/run = 3/2. The line crosses the axes at x=-2 and y=3, the intercepts.

8 0

2 years ago

Find the quotient in their exponential form.

vodomira [7]

Answer:

0.609663161

Step-by-step explanation:

(8/27)power5 = 5.57533755

(2/3)power7= 9.14494717

then, u just devide... from what i know

6 0

2 years ago

Read 2 more answers

Suppose y = 2x + 1 , where x and y are functions of t. (a) if dx/dt = 3, find dy/dt when x = 4. dy dt = (b) if dy/dt = 2, find d

qwelly [4]

Answer:

Step-by-step explanation:

If y = 2x + 1, then dy/dt = 2(dx/dt).

If y = 2x + 1, then y = 2(40) + 1 when 40 is substituted for x. y = 81.

(a) if dx/dt = 3, find dy/dt when x = 4:

Replacing dx/dt with 3 in dy/dt = 2(dx/dt) yields dy/dt = 2(3) = 6.

(b) if dy/dt = 2, find dx/dt when x = 40:

Replacing dy/dt with 2 in dy/dt = 2(dx/dt) results in 2 = 2(dx/dt), so dx/dt must be 1.

3 0

2 years ago

An orange grove produces a profit of $ 100 per tree when there are 1300 trees planted. Because of overcrowding, the profit per

Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

(x) = (1100 + x) (100 - .05(x-1100))

This is a quadratic, graphs as a parabola that opens downward. A maximum cam be found.

The zeros of the function are

(1100 + x) = 0 ..... or ..... [100 - .05(x-1100)] = 0

x = -1100 is the left x-intercept.

[100 - .05(x-1100)] = 0

100 = .05(x-1100)

2000 = x - 1100

x = 3100 is the right intercept.

Maximization of profits is at the mid point of the zeros (x-intercepts)

(3100 + -1100)/2 = 1000

1100 + 1000 = 2100 trees should be planted to maximize profits.

f(x) = (1100 + 1000) (100 - .05(1000-1100))

f(x) = (2000) (105) = 220,500 is the maximum profit.

I hope this helps!

4 0

3 years ago