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Sveta_85 [38]
3 years ago
11

at a school

Mathematics
2 answers:
dezoksy [38]3 years ago
8 0

Answer:

Total students  = 1240

Step-by-step explanation:

Boys : girls = 11 : 9

Number of boys  = 11x

Number of girls  = 9x

11x - 9x = 124

       2x = 124

         x = 124/2

        x = 62

Number of boys  = 11x = 11 *62 = 682

Number of girls  = 9x   = 9*62    = 558

Total students  = 682 + 558 = 1240

bonufazy [111]3 years ago
5 0

Answer:

1240 students.

Step-by-step explanation:

There are 558 girls and 682 boys

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julia-pushkina [17]
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Explanation:
The linear (line) equation is:
y = mx + c

Where
m = slope = rise/run = -0.3/2 = -0.15 (negative sign indicates the downward slope)
c = y-intercept = 1.95 (in graph)

Plug in the values in line equation:
y = -0.15x + 1.95 (Option D)</span>
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3 years ago
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What is the answer to this problem
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Baxter ate 1/12, so now the box is 3/4 - 9/12 full. So, (1/12) + (9/12) = 10/12.

10/12 of full box was there before Baxter ate.
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4 years ago
Round 1.965 to the nearest tenth.
Ne4ueva [31]

Answer: 2.0

Step-by-step explanation:

To round 1.965 to the nearest tenth consider the hundredths’ value of 1.965, which is 6 and equal or more than 5. Therefore, the tenths value of 1.965 increases by 1 to 0.

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3 years ago
4) Expand and simplify<br> 5(x-3) - 3 (x + 5)
Nezavi [6.7K]

Answer:

2x-30

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7 0
1 year ago
following frequency distribution shows the daily expenditure on milk of 30 households in a locality:Daily expenditure on milk(in
valina [46]

<em>Note:</em> <em>As you missed to identify what we have to find in this question. But, after a little research, I am able to find that we had to find the Mode for the data given in your question. So, I am assuming we have to calculate the the Mode. Hopefully, it would clear your concept regarding this topic.</em>

Answer:

The mode of the data = 75

Step-by-step explanation:

Lets visualize the given data in a table to show the frequency distribution:

<em>Daily expenditure on milk (in Rs)           Number of households</em>

<em>                  0-30                                                           5</em>

<em>                 30-60                                                          6        </em>

<em>                 60-90                                                          9</em>

<em>                 90-120                                                         6</em>

<em>                 120-150                                                        4</em>

Here the maximum frequency is 9.

So, modal class is <em>60-90.</em>

<em />

As the formula to calculate the mode:

Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )

Here, the maximum

l_{1} =60, f_{1} =9, f_{0}=6, f_{0}=6, h=30

l= is the lower limit of the class

f_{1} = is the frequency of the modal class

f_{0} = is the frequency of the previous modal class

f_{2} = is the frequency of the next previous modal class

l= is the class size

So,

Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )

Mode = 60 + 30 (\frac{9-6}{2(9)-6-6} )

Mode = 60 + \frac{(30)(3)}{6}

Mode = 60 + 15=75

∴ The mode of the data = 75

<em>Keywords: mode, frequency distribution</em>

<em> Learn more about mode and frequency distribution from brainly.com/question/14354368</em>

<em> #learnwithBrainly </em>

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