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natali 33 [55]
3 years ago
13

Elena divided a decimal by a whole number. 84.36 ÷ 12 = ? Part A: Explain each step needed to divide 84.3y by 12. Part B: What i

s the correct qoutient?
Mathematics
1 answer:
Iteru [2.4K]3 years ago
7 0

Answer:

Part A. \frac{84.3y}{12} = 7 +\frac{0.1\cdot y}{4}

Part B. The correct quotient is (3 × 4)

Step-by-step explanation:

Part A.

To divide 84.36 by 12 we look for the Highest Common Factor of the whole number and the decimal portions of the numerator and the denominator individually as follows;

\frac{84.36}{12} = \frac{84+0.3636}{12}  =  \frac{2 \times 2 \times 3  \times 7+0.01\times 12\times 3}{12} =  \frac{12  \times 7+0.03\times 12}{12}

Therefore, dividing 84.36 by 12 gives \frac{12  \times 7+0.03\times 12}{12} = 7+0.03 = 7.03

When dividing 84.3·y by 12, therefore, we have;

\frac{12  \times 7+0.3\times y}{12} = 7 +\frac{0.1\cdot y}{4}

Part B.

The correct quotient should have factors of the numerator

Therefore the divisor 12 should be represented as follows

\frac{12  \times 7+0.3\times y}{12} =\frac{12  \times 7+0.3\times y}{3 \times 4}

The correct quotient therefore = (3 × 4)

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Let X represent the full height of a certain species of tree. Assume that X has a normal distribution with a mean of 137.1 ft an
Rama09 [41]

Answer:

0.0668 = 6.68% probability that the height of a randomly selected tree is as tall as mine or shorter.

0.0228 = 2.28% probability that the full height of a randomly selected tree is at least as tall as hers.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 137.1, \sigma = 3.2

A tree of this type grows in my backyard, and it stands 132.3 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter.

This is the pvalue of Z when X = 132.3. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{132.3 - 137.1}{3.2}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 = 6.68% probability that the height of a randomly selected tree is as tall as mine or shorter.

My neighbor also has a tree of this type growing in her backyard, but hers stands 143.5 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers.

This is 1 subtracted by the pvalue of Z when X = 143.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{143.5 - 137.1}{3.2}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the full height of a randomly selected tree is at least as tall as hers.

7 0
3 years ago
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