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3 years ago

Consider the graph of the linear equation 2x - 5y = 10.

Mathematics

1 answer:

Artist 52 [7]3 years ago

7 0

Answer:

y = 2/5x - 2

Step-by-step explanation:

Subtract x to the other side to get -5y = -2x + 10. Divide -2x + 10 by -5 to get the answer.

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Obasi earns 150%, percent of his regular hourly wage while working overtime. What fraction of his regular hourly wage does Obasi

hammer [34]

Obasi earns 150% of his regular hourly wage while working overtime.

Let us convert percentage into fraction first:

To convert a percentage into fraction we need to use the following formula:

a% $=\frac{a}{100}$

Here, he earns 150% of his hourly wage while working overtime:

So,

150%= $=\frac{150}{100} =\frac{3}{2} =1.5$

Obasi earns $\frac{3}{2}$ of his hourly earnings or 1.5 times of his hourly earnings while working overtime.

8 0

4 years ago

Read 2 more answers

A student factors a^6-64 to (a^2-4)(a^4+4a^2+16) is correct

TiliK225 [7]

Answer:

yes

Step-by-step explanation:

hope this helps

5 0

3 years ago

Mr. Brown is creating examples of systems of equations. He completes the steps to find the solution of the equation below.

beks73 [17]

Answer:

Option D.

Step-by-step explanation:

The given system of equations is

$5x+2y=8$ ...(1)

$-4(1.25x+0.5y=2)$ ...(2)

On simplifying the second equation, we get

$-5x-2y=-8$

On dividing by -1, we get

$5x+2y=8$ ...(3)

It is clear that equation (1) and (3) are same equations. It means equation (1) and (2) represent the equivalent equation.

So, the given system of equations has infinitely many solutions.

Therefore, the correct option is D.

6 0

4 years ago

A polynomial has one root that equals 4+17i name one other root of this polynomial

Lapatulllka [165]

In any polynomial when you have an imaginary root, there is always another imaginary root that is the conjugate of the first one:
1st root: 4 + 17i
2nd root: 4 - 17i (the conjugate of the 1st one)

6 0

3 years ago

Read 2 more answers

Suppose you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by model

Ann [662]

Answer:

(1) The degrees of freedom for unequal variance test is (14, 11).

(2) The decision rule for the 0.01 significance level is;

If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.

If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.

(3) The value of the test statistic is 0.3796.

Step-by-step explanation:

We are given that you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by models featuring Liz Claiborne's attire with those of Calvin Klein.

The following is the amount ($000) earned per month by a sample of 15 Claiborne models;

$3.5, $5.1, $5.2, $3.6, $5.0, $3.4, $5.3, $6.5, $4.8, $6.3, $5.8, $4.5, $6.3, $4.9, $4.2 .

The following is the amount ($000) earned by a sample of 12 Klein models;

$4.1, $2.5, $1.2, $3.5, $5.1, $2.3, $6.1, $1.2, $1.5, $1.3, $1.8, $2.1.

(1) As we know that for the unequal variance test, we use F-test. The degrees of freedom for the F-test is given by;

$\text{F}_(_n__1-1, n_2-1_)$

Here, $n_1$ = sample of 15 Claiborne models

$n_2$ = sample of 12 Klein models

So, the degrees of freedom = ( $n_1-1, n_2-1$ ) = (15 - 1, 12 - 1) = (14, 11)

(2) The decision rule for 0.01 significance level is given by;

If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.

If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.

(3) The test statistics that will be used here is F-test which is given by;

T.S. = $\frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }$ ~ $\text{F}_(_n__1-1, n_2-1_)$

where, $s_1^{2}$ = sample variance of the Claiborne models data = $\frac{\sum (X_i-\bar X)^{2} }{n_1-1}$ = 1.007

$s_2^{2}$ = sample variance of the Klein models data = $\frac{\sum (X_i-\bar X)^{2} }{n_2-1}$ = 2.653

So, the test statistics = $\frac{1.007}{2.653 } \times 1$ ~ $\text{F}_(_1_4,_1_1_)$

= 0.3796

Hence, the value of the test statistic is 0.3796.

3 0

3 years ago