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3 years ago

Trigonometry

Mathematics

2 answers:

xz_007 [3.2K]3 years ago

4 0

Answer:

60º

Step-by-step explanation:

Using unit circle you can count up until you get the answer of 60º. Alternatively you can multiply 2pi/6 by 180/pi which will give you the same answer.

statuscvo [17]3 years ago

4 0

Answer:60°

Step-by-step explanation:

Using unit circle you can count up until you get the answer of 60º

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The wound in the ....... took a long time to ....... .

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The wound in the heel took a long time to heal.

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3 years ago

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Three students have started a fence-painting business. Working together, Pragnesh and Qazi can paint the fence in 12 hours. Simi

Mila [183]

Step-by-step explanation:

P and Q can do the whole work in 12 hours.

so, in 1 hour they can do 1/12.

P and R can do in 1 hour 1/15.

Q and R can do in 1 hour 1/20.

mathematically that looks like

P + Q = 1/12

P + R = 1/15

Q + R = 1/20

P + Q + R = 1/x

together they can do 1/x of the work in 1 hour.

it will take them x hours, if all 3 worked together.

from the first equation we get

P = 1/12 - Q

that gives us in the second equation

1/12 - Q + R = 1/15

R = 1/15 - 1/12 + Q = 4/60 - 5/60 + Q = Q - 1/60

but from the 3rd equation we get also

R = 1/20 - Q

so,

Q - 1/60 = 1/20 - Q

2Q = 1/20 + 1/60 = 3/60 + 1/60 = 4/60

Q = 2/60 = 1/30

R = Q - 1/60 = 2/60 - 1/60 = 1/60

P = 1/12 - Q = 1/12 - 2/60 = 5/60 - 2/60 = 3/60 = 1/20

so, we get for the sum :

P + Q + R = 3/60 + 2/60 + 1/60 = 6/60 = 1/10

that means in 1 hour they can do together 1/10 of the work.

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2 years ago

Five times the sum of a number and 27 is greater than or equal to six times the sum of that

AleksAgata [21]

The complete version of question:

Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.

Answer:

$5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}$

Step-by-step explanation:

As the description of the statement is:

'Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.

Five times the sum of a number and 27 is written as: $5(x + 27)$

greater than or equal is written as: $\geq$

six times the sum of that number and 26' is written as: 6(x + 26)

so lets combine the whole statement:

$5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)$

solving

$5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)$

$5x+135\ge \:6x+156$

$5x+135-135\ge \:6x+156-135$

$5x\ge \:6x+21$

$5x-6x\ge \:6x+21-6x$

$-x\ge \:21$

$\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}$

$\left(-x\right)\left(-1\right)\le \:21\left(-1\right)$

$x\le \:-21$

Therefore,

$5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}$

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3 years ago

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It would be 104? I don’t understand the question but I guessing you’re adding

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4 years ago

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