All categories

3 years ago

Solve for b -8b-14+5b=11

Mathematics

2 answers:

gavmur [86]3 years ago

5 0

I hope this helps you

Natasha_Volkova [10]3 years ago

5 0

-8b - 14 + 5b = 11...simplify
-3b - 14 = 11...add 14 to both sides
-3b = 11 + 14
-3b = 25
b = -25/3 or -8 1/3

You might be interested in

I’ll mark Brainiest?

Usimov [2.4K]

The answer is D. Group =2

8 0

3 years ago

Фd —<br> 969 - 9<br> ХОТХЭ: <br> P

oee [108]

brainly.com/question/24478767

5 0

3 years ago

Find three consecutive even integers such that the square of the third is 60 more that the square of the second

lana [24]

Answer:

-4,4,16

Step-by-step explanation:

They are all even integers.

-4^2=16

4^2=16

16^2=256

the square of the third,16 is 256 which is more than the square of the second,4=16

4 0

3 years ago

Which of these strategies would eliminate a variable in the system of equations?

melomori [17]

5x -2y = 2 is the answer

8 0

2 years ago

The picture shows a triangular island:

sergiy2304 [10]

Answer:

The expressions that show the value of q are

1) $q=\sqrt{r^{2}+s^{2}}$

2) $q=\frac{s}{cos(55\°)}$

3) $q=\frac{r}{sin(55\°)}$

4) $q=\frac{s}{sin(35\°)}$

5) $q=\frac{r}{cos(35\°)}$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

case A)

In the right triangle of the figure

Applying the Pythagoras Theorem

$q^{2}=r^{2}+s^{2}$

$q=\sqrt{r^{2}+s^{2}}$

case B)

In the right triangle of the figure

$cos(55\°)=\frac{s}{q}$

solve for q

$q=\frac{s}{cos(55\°)}$

case C)

In the right triangle of the figure

$sin(55\°)=\frac{r}{q}$

solve for q

$q=\frac{r}{sin(55\°)}$

case D)

In a right triangle

if $A+B=90\°$

then

$cos(A)=sin(B)$

therefore

$q=\frac{s}{cos(55\°)}$ ------> $q=\frac{s}{sin(35\°)}$

$q=\frac{r}{sin(55\°)}$ ------> $q=\frac{r}{cos(35\°)}$

4 0

3 years ago

Read 2 more answers