Answer:
Step-by-step explanation:
Numerator: 2^3
Denominator: 2^(1/2)
Combining these, we subtract 1/2 from 3, obtaining 2^(5/2)
Given two functions are
f(x) = 2 cos(x)
g(x) = 3 sin(x+ )
We know that the maximum value of cos x and sin x is always 1
y= maximum of cos = 1
y= maximum of sin =1
f(x) = 2 cos(x)
y= 2 (max of cos) = 2(1) = 2
g(x) = 3 sin(x+ )
y= 3 (max of sin) = 3(1) = 3
g(x) = 3 sin(x+ ) has the maximum value.
The answer to this is 36.
Let's first write the equation given
x²+6x-13=0
They have told us to use "Completing the square" method.
So we need write x²+6x-13 as a whole square.
x²+6x-13=0
x²+(2*3*x)-9-4 = 0
x²+(2*3*x)-3²=4
Now we can write the LHS as:
(x - 3)²=2²
Hence,
x-3 can either be 2 or -2
Now,
x - 3=2
x=5
Or,
x - 3=-2
x=1
Therefore now we know that x can either be 1 or 5. So the correct answer is Option B.