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vlada-n [284]
3 years ago
5

Write the slope-intercept form of the equation with the given characteristics.

Mathematics
1 answer:
Serhud [2]3 years ago
7 0

Answer:

1. y=1/4x+2

2. y=-3/2x +1

3. y = -3/2x -2

4. y= -3x -49

5. y = -2x +8

Step-by-step explanation:

1. Use slope intercept, y=mx+b where m =1/4 and b=2. y=1/4x+2

2. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.  

(y-7)=-3/2(x--4)  

y-7=-3/2(x+4)

y-7=-3/2x-6

y = -3/2x -6 +7

y=-3/2x +1


3. To write the equation of a line we must have a slope and a point. To find the slope we use the slope formula and substitute (x,y) points in it as shown below:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{-5-1}{2--2}=\frac{-5+-1}{2+2}=\frac{-6}{4}=\frac{-3}{2}

Now that we have the slope, plug in the slope and choose one point to plug into the point slope formula. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.  

(y--5)=-3/2(x-2)  

y+5=-3/2(x-2)

y+5=-3/2x + 3

y = -3/2x -2

4. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form. The slope is -3 since parallel lines have the same slope.  

(y--4)=-3(x-5)  

y+4=-3 (x+15)

y+4=-3x -45

y= -3x -49

5. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form. The slope is -2 since perpendicular lines have the negative reciprocal slopes. So 1/2 becomes -2.

(y--6)=-2(x-7)  

y+6=-2 (x-7)

y+6 = -2x + 14

y = -2x +8

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Answer:

Solutions: x = \frac{-3}{ 4} + i \sqrt{39},  x = \frac{-3}{4} - i \sqrt{39}

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

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