Please help me with this question please clarify what you're saying thank you

Mathematics

1 answer:

timurjin [86]3 years ago

3 0

The question is asking for the circumference
The equation for circumference is C=2(Pi)r<span>

</span>to find the radius, half the diameter 4/2=2

the equation is now C=2(Pi)2<span>
simplify the equation...
C=4(Pi)
Pi is </span>3.1415926535897932384626433832795

Now multiply 3.1415926535897932384626433832795 times 4 = 12.566370614359172953850573533118
Round to nearest tenth...

12.6 mi

You might be interested in

Suden wants to know the theoretical and experimental probability of rolling a number smaller than a 3 on a 6-sided number cube n

MakcuM [25]

Answer:

The theoretical probability of rolling a number smaller than a 3 is __1/3_____because this is what__we expect to happen____ . The experimental probability of rolling a number smaller than a 3 is __1/4____ because this is what___actually happened____

Step-by-step explanation:

The experimental probability is

P (<3) = ( getting a one or 2)/ number of times that he rolled

He rolled a one or a two 2 times of the 8 times rolled

= 2/8 = 1/4

Theoretical probability is what we expect happen

P (<3) = (getting a one or two) / 6

= 2/6 = 1/3

4 0

3 years ago

The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1

Aleksandr-060686 [28]

Answer:

a) The probability that a student has either a Visa card or a MasterCard is 0.71.

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b) In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards is $P(V \cap M)=0.03$