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Mashutka [201]
3 years ago
12

Please help me with this question please clarify what you're saying thank you

Mathematics
1 answer:
timurjin [86]3 years ago
3 0
The question is asking for the circumference
The equation for circumference is C=2(Pi)r<span>

</span>to find the radius, half the diameter 4/2=2

the equation is now C=2(Pi)2<span>
simplify the equation...
C=4(Pi)
Pi is </span>3.1415926535897932384626433832795

Now multiply 3.1415926535897932384626433832795 times 4 = 12.566370614359172953850573533118
Round to nearest tenth...

12.6 mi
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Find (fºg)(1)<br> f(x) = x² - 1<br> g(x) = √x <br> A.0<br> B.1<br> C.4 √2<br> D. √8
Savatey [412]

Given:

The function are

f(x)=x^2-1

g(x)=\sqrt{x}

To find:

The value of (f\circ g)(1).

Solution:

We have,

f(x)=x^2-1

g(x)=\sqrt{x}

We need to find the value of (f\circ g)(1).

(f\circ g)(1)=f(g(1))            [\because (f\circ g)(x)=f(g(x))]

(f\circ g)(1)=f(\sqrt{1})            [\because g(x)=\sqrt{x}]

(f\circ g)(1)=f(1)      

(f\circ g)(1)=(1)^2-1                  [\because f(x)=x^2-1]

(f\circ g)(1)=1-1      

(f\circ g)(1)=0      

The value of (f\circ g)(1) is 0.

Therefore, the correct option is A.

4 0
3 years ago
The length of a rectangle is 3131 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
Gala2k [10]

We have a rectangle with a diagonal included. That means we have to use Pythagorean's Theorem to find the missing dimensions. We start with the width as w. The length is 31 more than twice the width, so the length is 2w+31. The hypotenuse (diagonal) is 2 more than the length, so the diagonal measures 2w+33. In a right triangle, the hypotenuse is always the longest side, so we set up Pythagorean's Theorem using the bolded values as such: (2w+33)^2=w^2+(2w+31)^2. Distributing by multiplying we simplify to 4w^2+132w+1089=w^2+4w^2+124w+961. We need to solve for w. Once we do that we can use that value to find the length. What's nice is that the 4w^2 terms cancel each other out. So when we combine like terms and get them all on one side of the equals sign to factor we have w^2-8w-128=0. The 2 numbers that add up to -8 and multiply to -128 are 16 and -8. So the width is either 16 inches or the width is -8 inches. The 2 things in math that will never EVER be negative are time and distance/length. So -8 is out. The width is 16 inches. That means that the length is 2(16)+31, which is 63 inches. There you go!

8 0
3 years ago
Find the quotient of the problem using the area model strategy. After you have worked out your problems on a sheet of paper, you
Artist 52 [7]

Answer:

56 with re9

Step-by-step explanation make a square on a paper make 3 line on top of each line put 800 40 and 9 on the side put 15 search up 15 dived by 800 and 40 dived by 15 then 9 add it all up the yo go give me brainlist

8 0
3 years ago
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What is the solution of -x+4&gt;2
Svetradugi [14.3K]

There is no single solution but there is a group of solutions also known as the interval.

-x+4>2 \\-x>-2 \\x

This can be written with an interval.

x\in(-\infty, 2)

Hope this helps.

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6 0
3 years ago
C
mario62 [17]

Answer:

since the sum of interior angles of hexagon is 720 °

you add the known angles

ie 115 +90+145+160

you get 510

subtract it from 720

you get 210

divide 210 by 3

you get 70

angle cde is 140

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3 years ago
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