The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
<h3>What is the derivative of the function g(x) by virtue of the Fundamental theorem of calculus as given in the task content?</h3>
g(x) = Integral; √2 ln(t) dt (with the upper and lower limits e^x and 1 respectively).
Since, it follows from the Fundamental theorem of calculus that given an integral where;
Now, g(x) = Integral f(t) dt with limits a and x, it follows that the differential of g(x);
g'(x) = f(x).
Consequently, the function g'(x) which is to be evaluated in this scenario can be determined as:
g'(x) =
= 1
The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
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The answer is 5.5
In a rectangle, lengths of diagonals are equal. If you draw the rectangle, you can see that KM and LN are diagonals, so they must be equal:
KM = LN
KM = 6x + 16
LN = 49
6x + 16 = 49
6x = 49 - 16
6x = 33
x = 33/6
x = 5.5
The correct answer I believe you are looking for is D. Elevator 1 is 13 feet above ground level, and Elevator 2 is 10 feet below ground level.
<u>Explaination:</u>
This is because if you start at (0, 0) Elevator one, will go up 13 on the y axis. Putting it at 13 feet above ground level. If you start Elevator 2 at ground level on (0, 0) and go down 10 it will make it -10 AKA 10 feet below ground level.
I hope this helps! :)